Whakaoti i te 3x/(x^2-4)=

$$\frac { 3 x } { ( x ^ { 2 } - 4 ) } =$$

Kimi Pārōnaki e ai ki x

$$-\frac{3\left(x^{2}+4\right)}{\left(x^{2}-4\right)^{2}}$$

Ngā Upane e Whakamahi ana i te Ture Pārōnaki mō te Otinga

Mō ngā pānga e rua e taea ana te pārōnaki, ko te pārōnaki o te otinga o ngā pānga e rua ko te tauraro whakareatia ki te pārōnaki o te taurunga tango i te taurunga whakareatia ki te pārōnaki o te tauraro, ā, ka whakawehea te katoa ki te tauraro kua pūruatia.

$$\frac{\left(x^{2}-4\right)\frac{\mathrm{d}}{\mathrm{d}x}(3x^{1})-3x^{1}\frac{\mathrm{d}}{\mathrm{d}x}(x^{2}-4)}{\left(x^{2}-4\right)^{2}}$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$\frac{\left(x^{2}-4\right)\times 3x^{1-1}-3x^{1}\times 2x^{2-1}}{\left(x^{2}-4\right)^{2}}$$

Mahia ngā tātaitanga.

$$\frac{\left(x^{2}-4\right)\times 3x^{0}-3x^{1}\times 2x^{1}}{\left(x^{2}-4\right)^{2}}$$

Whakarohaina mā te āhuatanga tohatoha.

$$\frac{x^{2}\times 3x^{0}-4\times 3x^{0}-3x^{1}\times 2x^{1}}{\left(x^{2}-4\right)^{2}}$$

Hei whakarea pū o te pūtake ōrite, tāpiri ana taupū.

$$\frac{3x^{2}-4\times 3x^{0}-3\times 2x^{1+1}}{\left(x^{2}-4\right)^{2}}$$

Mahia ngā tātaitanga.

$$\frac{3x^{2}-12x^{0}-6x^{2}}{\left(x^{2}-4\right)^{2}}$$

Pahekotia ngā kīanga tau ōrite.

$$\frac{\left(3-6\right)x^{2}-12x^{0}}{\left(x^{2}-4\right)^{2}}$$

Tango 6 mai i 3.

$$\frac{-3x^{2}-12x^{0}}{\left(x^{2}-4\right)^{2}}$$

Tauwehea te 3.

$$\frac{3\left(-x^{2}-4x^{0}\right)}{\left(x^{2}-4\right)^{2}}$$

Mō tētahi kupu t mahue te 0, t^{0}=1.

$$\frac{3\left(-x^{2}-4\right)}{\left(x^{2}-4\right)^{2}}$$

Aromātai

$$\frac{3x}{x^{2}-4}$$