Whakaoti i te 3x^2y^3/27xy^3

$$\frac { 3 x ^ { 2 } y ^ { 3 } } { 27 x y ^ { 3 } }$$

Aromātai

$$\frac{x}{9}$$

Ngā Upane e Whakamahi ana i te Āhuatanga o te Otinga o ngā Pū

Whakamahia ngā ture taupū hei whakarūnā i te kīanga.

$$\frac{3^{1}x^{2}y^{3}}{27^{1}x^{1}y^{3}}$$

Hei whakawehe i ngā pū o te pūtake kotahi, tangohia te taupū o te tauraro mai i te taupū o te taurunga.

$$\frac{3^{1}}{27^{1}}x^{2-1}y^{3-3}$$

Tango 1 mai i 2.

$$\frac{3^{1}}{27^{1}}x^{1}y^{3-3}$$

Tango 3 mai i 3.

$$\frac{3^{1}}{27^{1}}xy^{0}$$

Mō tētahi tau a mahue te 0, a^{0}=1.

$$\frac{3^{1}}{27^{1}}x$$

Whakahekea te hautanga \frac{3}{27} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 3.

$$\frac{1}{9}x$$

Kimi Pārōnaki e ai ki x

$$\frac{1}{9} = 0.1111111111111111$$

Ngā Upane Otinga

Hei whakawehe i ngā pū o te pūtake kotahi, tangohia te taupū o te tauraro mai i te taupū o te taurunga.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{3y^{3}}{27y^{3}}x^{2-1})$$

Mahia ngā tātaitanga.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{1}{9}x^{1})$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$\frac{1}{9}x^{1-1}$$

Mahia ngā tātaitanga.

$$\frac{1}{9}x^{0}$$

Mō tētahi kupu t mahue te 0, t^{0}=1.

$$\frac{1}{9}\times 1$$

Mō tētahi kupu t, t\times 1=t me 1t=t.

$$\frac{1}{9}$$