Whakaoti i te 3x^2+4-5/x^2+5x+4-2x/x+1+4/x+4

$$\frac { 3 x ^ { 2 } + 4 - 5 } { x ^ { 2 } + 5 x + 4 } - \frac { 2 x } { x + 1 } + \frac { 4 } { x + 4 }$$

Aromātai

$$\frac{\left(x-3\right)\left(x-1\right)}{\left(x+1\right)\left(x+4\right)}$$

Ngā Hipanga Rongoā Poto

Tangohia te 5 i te 4, ka -1.

$$\frac{3x^{2}-1}{x^{2}+5x+4}-\frac{2x}{x+1}+\frac{4}{x+4}$$

Tauwehea te x^{2}+5x+4.

$$\frac{3x^{2}-1}{\left(x+1\right)\left(x+4\right)}-\frac{2x}{x+1}+\frac{4}{x+4}$$

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Ko te taurea pātahi iti rawa o \left(x+1\right)\left(x+4\right) me x+1 ko \left(x+1\right)\left(x+4\right). Whakareatia \frac{2x}{x+1} ki te \frac{x+4}{x+4}.

$$\frac{3x^{2}-1}{\left(x+1\right)\left(x+4\right)}-\frac{2x\left(x+4\right)}{\left(x+1\right)\left(x+4\right)}+\frac{4}{x+4}$$

Tā te mea he rite te tauraro o \frac{3x^{2}-1}{\left(x+1\right)\left(x+4\right)} me \frac{2x\left(x+4\right)}{\left(x+1\right)\left(x+4\right)}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{3x^{2}-1-2x\left(x+4\right)}{\left(x+1\right)\left(x+4\right)}+\frac{4}{x+4}$$

Mahia ngā whakarea i roto o 3x^{2}-1-2x\left(x+4\right).

$$\frac{3x^{2}-1-2x^{2}-8x}{\left(x+1\right)\left(x+4\right)}+\frac{4}{x+4}$$

Whakakotahitia ngā kupu rite i 3x^{2}-1-2x^{2}-8x.

$$\frac{x^{2}-1-8x}{\left(x+1\right)\left(x+4\right)}+\frac{4}{x+4}$$

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Ko te taurea pātahi iti rawa o \left(x+1\right)\left(x+4\right) me x+4 ko \left(x+1\right)\left(x+4\right). Whakareatia \frac{4}{x+4} ki te \frac{x+1}{x+1}.

$$\frac{x^{2}-1-8x}{\left(x+1\right)\left(x+4\right)}+\frac{4\left(x+1\right)}{\left(x+1\right)\left(x+4\right)}$$

Tā te mea he rite te tauraro o \frac{x^{2}-1-8x}{\left(x+1\right)\left(x+4\right)} me \frac{4\left(x+1\right)}{\left(x+1\right)\left(x+4\right)}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$\frac{x^{2}-1-8x+4\left(x+1\right)}{\left(x+1\right)\left(x+4\right)}$$

Mahia ngā whakarea i roto o x^{2}-1-8x+4\left(x+1\right).

$$\frac{x^{2}-1-8x+4x+4}{\left(x+1\right)\left(x+4\right)}$$

Whakakotahitia ngā kupu rite i x^{2}-1-8x+4x+4.

$$\frac{x^{2}+3-4x}{\left(x+1\right)\left(x+4\right)}$$

Whakarohaina te \left(x+1\right)\left(x+4\right).

$$\frac{x^{2}+3-4x}{x^{2}+5x+4}$$

Whakaroha

$$\frac{x^{2}-4x+3}{\left(x+1\right)\left(x+4\right)}$$

Ngā Hipanga Rongoā Poto

Tangohia te 5 i te 4, ka -1.

$$\frac{3x^{2}-1}{x^{2}+5x+4}-\frac{2x}{x+1}+\frac{4}{x+4}$$

Tauwehea te x^{2}+5x+4.

$$\frac{3x^{2}-1}{\left(x+1\right)\left(x+4\right)}-\frac{2x}{x+1}+\frac{4}{x+4}$$

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Ko te taurea pātahi iti rawa o \left(x+1\right)\left(x+4\right) me x+1 ko \left(x+1\right)\left(x+4\right). Whakareatia \frac{2x}{x+1} ki te \frac{x+4}{x+4}.

$$\frac{3x^{2}-1}{\left(x+1\right)\left(x+4\right)}-\frac{2x\left(x+4\right)}{\left(x+1\right)\left(x+4\right)}+\frac{4}{x+4}$$

Tā te mea he rite te tauraro o \frac{3x^{2}-1}{\left(x+1\right)\left(x+4\right)} me \frac{2x\left(x+4\right)}{\left(x+1\right)\left(x+4\right)}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{3x^{2}-1-2x\left(x+4\right)}{\left(x+1\right)\left(x+4\right)}+\frac{4}{x+4}$$

Mahia ngā whakarea i roto o 3x^{2}-1-2x\left(x+4\right).

$$\frac{3x^{2}-1-2x^{2}-8x}{\left(x+1\right)\left(x+4\right)}+\frac{4}{x+4}$$

Whakakotahitia ngā kupu rite i 3x^{2}-1-2x^{2}-8x.

$$\frac{x^{2}-1-8x}{\left(x+1\right)\left(x+4\right)}+\frac{4}{x+4}$$

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Ko te taurea pātahi iti rawa o \left(x+1\right)\left(x+4\right) me x+4 ko \left(x+1\right)\left(x+4\right). Whakareatia \frac{4}{x+4} ki te \frac{x+1}{x+1}.

$$\frac{x^{2}-1-8x}{\left(x+1\right)\left(x+4\right)}+\frac{4\left(x+1\right)}{\left(x+1\right)\left(x+4\right)}$$

Tā te mea he rite te tauraro o \frac{x^{2}-1-8x}{\left(x+1\right)\left(x+4\right)} me \frac{4\left(x+1\right)}{\left(x+1\right)\left(x+4\right)}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$\frac{x^{2}-1-8x+4\left(x+1\right)}{\left(x+1\right)\left(x+4\right)}$$

Mahia ngā whakarea i roto o x^{2}-1-8x+4\left(x+1\right).

$$\frac{x^{2}-1-8x+4x+4}{\left(x+1\right)\left(x+4\right)}$$

Whakakotahitia ngā kupu rite i x^{2}-1-8x+4x+4.

$$\frac{x^{2}+3-4x}{\left(x+1\right)\left(x+4\right)}$$

Whakarohaina te \left(x+1\right)\left(x+4\right).

$$\frac{x^{2}+3-4x}{x^{2}+5x+4}$$