Whakaoti i te 3s^5t/3s^5t^7=

$$\frac { 3 s ^ { 5 } t } { 3 s ^ { 5 } t ^ { 7 } } =$$

Aromātai

$$\frac{1}{t^{6}}$$

Ngā Upane e Whakamahi ana i te Āhuatanga o te Otinga o ngā Pū

Whakamahia ngā ture taupū hei whakarūnā i te kīanga.

$$\frac{3^{1}s^{5}t^{1}}{3^{1}s^{5}t^{7}}$$

Hei whakawehe i ngā pū o te pūtake kotahi, tangohia te taupū o te tauraro mai i te taupū o te taurunga.

$$3^{1-1}s^{5-5}t^{1-7}$$

Tango 1 mai i 1.

$$3^{0}s^{5-5}t^{1-7}$$

Mō tētahi tau a mahue te 0, a^{0}=1.

$$s^{5-5}t^{1-7}$$

Tango 5 mai i 5.

$$s^{0}t^{1-7}$$

Mō tētahi tau a mahue te 0, a^{0}=1.

$$t^{1-7}$$

Tango 7 mai i 1.

$$s^{0}t^{-6}$$

Mō tētahi kupu t mahue te 0, t^{0}=1.

$$1t^{-6}$$

Mō tētahi kupu t, t\times 1=t me 1t=t.

$$t^{-6}$$

Kimi Pārōnaki e ai ki t

$$-\frac{6}{t^{7}}$$

Ngā Upane e Whakamahi ana i te Ture Mekameka

Me whakakore tahi te 3ts^{5} i te taurunga me te tauraro.

$$\frac{\mathrm{d}}{\mathrm{d}t}(\frac{1}{t^{6}})$$

Mēnā ko F te hanganga o ngā pānga e rua e taea ana te pārōnaki f\left(u\right) me u=g\left(x\right), arā, mēnā ko F\left(x\right)=f\left(g\left(x\right)\right), ko te pārōnaki o F te pārōnaki o f e ai ki u whakareatia te pārōnaki o g e ai ki x, arā, \frac{\mathrm{d}}{\mathrm{d}x}(F)\left(x\right)=\frac{\mathrm{d}}{\mathrm{d}x}(f)\left(g\left(x\right)\right)\frac{\mathrm{d}}{\mathrm{d}x}(g)\left(x\right).

$$-\left(t^{6}\right)^{-1-1}\frac{\mathrm{d}}{\mathrm{d}t}(t^{6})$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$-\left(t^{6}\right)^{-2}\times 6t^{6-1}$$

Whakarūnātia.

$$-6t^{5}\left(t^{6}\right)^{-2}$$