Whakaoti i te 3/x-2-2/x+1

$$\frac { 3 } { x - 2 } - \frac { 2 } { x + 1 }$$

Aromātai

$$\frac{x+7}{\left(x-2\right)\left(x+1\right)}$$

Ngā Hipanga Rongoā Poto

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Ko te taurea pātahi iti rawa o x-2 me x+1 ko \left(x-2\right)\left(x+1\right). Whakareatia \frac{3}{x-2} ki te \frac{x+1}{x+1}. Whakareatia \frac{2}{x+1} ki te \frac{x-2}{x-2}.

$$\frac{3\left(x+1\right)}{\left(x-2\right)\left(x+1\right)}-\frac{2\left(x-2\right)}{\left(x-2\right)\left(x+1\right)}$$

Tā te mea he rite te tauraro o \frac{3\left(x+1\right)}{\left(x-2\right)\left(x+1\right)} me \frac{2\left(x-2\right)}{\left(x-2\right)\left(x+1\right)}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{3\left(x+1\right)-2\left(x-2\right)}{\left(x-2\right)\left(x+1\right)}$$

Mahia ngā whakarea i roto o 3\left(x+1\right)-2\left(x-2\right).

$$\frac{3x+3-2x+4}{\left(x-2\right)\left(x+1\right)}$$

Whakakotahitia ngā kupu rite i 3x+3-2x+4.

$$\frac{x+7}{\left(x-2\right)\left(x+1\right)}$$

Whakarohaina te \left(x-2\right)\left(x+1\right).

$$\frac{x+7}{x^{2}-x-2}$$

Kimi Pārōnaki e ai ki x

$$\frac{5-14x-x^{2}}{x^{4}-2x^{3}-3x^{2}+4x+4}$$

Ngā Upane e Whakamahi ana i te Ture Pārōnaki mō te Otinga

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Ko te taurea pātahi iti rawa o x-2 me x+1 ko \left(x-2\right)\left(x+1\right). Whakareatia \frac{3}{x-2} ki te \frac{x+1}{x+1}. Whakareatia \frac{2}{x+1} ki te \frac{x-2}{x-2}.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{3\left(x+1\right)}{\left(x-2\right)\left(x+1\right)}-\frac{2\left(x-2\right)}{\left(x-2\right)\left(x+1\right)})$$

Tā te mea he rite te tauraro o \frac{3\left(x+1\right)}{\left(x-2\right)\left(x+1\right)} me \frac{2\left(x-2\right)}{\left(x-2\right)\left(x+1\right)}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{3\left(x+1\right)-2\left(x-2\right)}{\left(x-2\right)\left(x+1\right)})$$

Mahia ngā whakarea i roto o 3\left(x+1\right)-2\left(x-2\right).

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{3x+3-2x+4}{\left(x-2\right)\left(x+1\right)})$$

Whakakotahitia ngā kupu rite i 3x+3-2x+4.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{x+7}{\left(x-2\right)\left(x+1\right)})$$

Me hoatu te āhuatanga tohatoha mā te whakarea ia tau o x-2 ki ia tau o x+1.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{x+7}{x^{2}+x-2x-2})$$

Pahekotia te x me -2x, ka -x.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{x+7}{x^{2}-x-2})$$

Mō ngā pānga e rua e taea ana te pārōnaki, ko te pārōnaki o te otinga o ngā pānga e rua ko te tauraro whakareatia ki te pārōnaki o te taurunga tango i te taurunga whakareatia ki te pārōnaki o te tauraro, ā, ka whakawehea te katoa ki te tauraro kua pūruatia.

$$\frac{\left(x^{2}-x^{1}-2\right)\frac{\mathrm{d}}{\mathrm{d}x}(x^{1}+7)-\left(x^{1}+7\right)\frac{\mathrm{d}}{\mathrm{d}x}(x^{2}-x^{1}-2)}{\left(x^{2}-x^{1}-2\right)^{2}}$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$\frac{\left(x^{2}-x^{1}-2\right)x^{1-1}-\left(x^{1}+7\right)\left(2x^{2-1}-x^{1-1}\right)}{\left(x^{2}-x^{1}-2\right)^{2}}$$

Whakarūnātia.

$$\frac{\left(x^{2}-x^{1}-2\right)x^{0}-\left(x^{1}+7\right)\left(2x^{1}-x^{0}\right)}{\left(x^{2}-x^{1}-2\right)^{2}}$$

Whakareatia x^{2}-x^{1}-2 ki te x^{0}.

$$\frac{x^{2}x^{0}-x^{1}x^{0}-2x^{0}-\left(x^{1}+7\right)\left(2x^{1}-x^{0}\right)}{\left(x^{2}-x^{1}-2\right)^{2}}$$

Whakareatia x^{1}+7 ki te 2x^{1}-x^{0}.

$$\frac{x^{2}x^{0}-x^{1}x^{0}-2x^{0}-\left(x^{1}\times 2x^{1}+x^{1}\left(-1\right)x^{0}+7\times 2x^{1}+7\left(-1\right)x^{0}\right)}{\left(x^{2}-x^{1}-2\right)^{2}}$$

Hei whakarea pū o te pūtake ōrite, tāpiri ana taupū.

$$\frac{x^{2}-x^{1}-2x^{0}-\left(2x^{1+1}-x^{1}+7\times 2x^{1}+7\left(-1\right)x^{0}\right)}{\left(x^{2}-x^{1}-2\right)^{2}}$$

Whakarūnātia.

$$\frac{x^{2}-x^{1}-2x^{0}-\left(2x^{2}-x^{1}+14x^{1}-7x^{0}\right)}{\left(x^{2}-x^{1}-2\right)^{2}}$$

Pahekotia ngā kīanga tau ōrite.

$$\frac{-x^{2}-14x^{1}+5x^{0}}{\left(x^{2}-x^{1}-2\right)^{2}}$$

Mō tētahi kupu t, t^{1}=t.

$$\frac{-x^{2}-14x+5x^{0}}{\left(x^{2}-x-2\right)^{2}}$$

Mō tētahi kupu t mahue te 0, t^{0}=1.

$$\frac{-x^{2}-14x+5\times 1}{\left(x^{2}-x-2\right)^{2}}$$

Mō tētahi kupu t, t\times 1=t me 1t=t.

$$\frac{-x^{2}-14x+5}{\left(x^{2}-x-2\right)^{2}}$$