Whakaoti i te 3/5x-2=x+1/3

$$\frac { 3 } { 5 } x - 2 = x + \frac { 1 } { 3 }$$

Whakaoti mō x

$$x = -\frac{35}{6} = -5\frac{5}{6} \approx -5.833333333$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tangohia te x mai i ngā taha e rua.

$$\frac{3}{5}x-2-x=\frac{1}{3}$$

Pahekotia te \frac{3}{5}x me -x, ka -\frac{2}{5}x.

$$-\frac{2}{5}x-2=\frac{1}{3}$$

Me tāpiri te 2 ki ngā taha e rua.

$$-\frac{2}{5}x=\frac{1}{3}+2$$

Me tahuri te 2 ki te hautau \frac{6}{3}.

$$-\frac{2}{5}x=\frac{1}{3}+\frac{6}{3}$$

Tā te mea he rite te tauraro o \frac{1}{3} me \frac{6}{3}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$-\frac{2}{5}x=\frac{1+6}{3}$$

Tāpirihia te 1 ki te 6, ka 7.

$$-\frac{2}{5}x=\frac{7}{3}$$

Me whakarea ngā taha e rua ki te -\frac{5}{2}, te tau utu o -\frac{2}{5}.

$$x=\frac{7}{3}\left(-\frac{5}{2}\right)$$

Me whakarea te \frac{7}{3} ki te -\frac{5}{2} mā te whakarea taurunga ki te taurunga me te tauraro ki te tauraro.

$$x=\frac{7\left(-5\right)}{3\times 2}$$

Mahia ngā whakarea i roto i te hautanga \frac{7\left(-5\right)}{3\times 2}.

$$x=\frac{-35}{6}$$

Ka taea te hautanga \frac{-35}{6} te tuhi anō ko -\frac{35}{6} mā te tango i te tohu tōraro.

$$x=-\frac{35}{6}$$