Whakaoti i te 3/5x+8=1/10(x-40)

$$\frac { 3 } { 5 } x + 8 = \frac { 1 } { 10 } ( x - 40 )$$

Whakaoti mō x

$$x=-24$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te \frac{1}{10} ki te x-40.

$$\frac{3}{5}x+8=\frac{1}{10}x+\frac{1}{10}\left(-40\right)$$

Whakareatia te \frac{1}{10} ki te -40, ka \frac{-40}{10}.

$$\frac{3}{5}x+8=\frac{1}{10}x+\frac{-40}{10}$$

Whakawehea te -40 ki te 10, kia riro ko -4.

$$\frac{3}{5}x+8=\frac{1}{10}x-4$$

Tangohia te \frac{1}{10}x mai i ngā taha e rua.

$$\frac{3}{5}x+8-\frac{1}{10}x=-4$$

Pahekotia te \frac{3}{5}x me -\frac{1}{10}x, ka \frac{1}{2}x.

$$\frac{1}{2}x+8=-4$$

Tangohia te 8 mai i ngā taha e rua.

$$\frac{1}{2}x=-4-8$$

Tangohia te 8 i te -4, ka -12.

$$\frac{1}{2}x=-12$$

Me whakarea ngā taha e rua ki te 2, te tau utu o \frac{1}{2}.

$$x=-12\times 2$$

Whakareatia te -12 ki te 2, ka -24.

$$x=-24$$