Whakaoti i te 3/4*(u-3)=1/3*(2u-5)

$$\frac { 3 } { 4 } \cdot ( u - 3 ) = \frac { 1 } { 3 } \cdot ( 2 u - 5 )$$

Whakaoti mō u

$$u=7$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te \frac{3}{4} ki te u-3.

$$\frac{3}{4}u+\frac{3}{4}\left(-3\right)=\frac{1}{3}\left(2u-5\right)$$

Tuhia te \frac{3}{4}\left(-3\right) hei hautanga kotahi.

$$\frac{3}{4}u+\frac{3\left(-3\right)}{4}=\frac{1}{3}\left(2u-5\right)$$

Whakareatia te 3 ki te -3, ka -9.

$$\frac{3}{4}u+\frac{-9}{4}=\frac{1}{3}\left(2u-5\right)$$

Ka taea te hautanga \frac{-9}{4} te tuhi anō ko -\frac{9}{4} mā te tango i te tohu tōraro.

$$\frac{3}{4}u-\frac{9}{4}=\frac{1}{3}\left(2u-5\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te \frac{1}{3} ki te 2u-5.

$$\frac{3}{4}u-\frac{9}{4}=\frac{1}{3}\times 2u+\frac{1}{3}\left(-5\right)$$

Whakareatia te \frac{1}{3} ki te 2, ka \frac{2}{3}.

$$\frac{3}{4}u-\frac{9}{4}=\frac{2}{3}u+\frac{1}{3}\left(-5\right)$$

Whakareatia te \frac{1}{3} ki te -5, ka \frac{-5}{3}.

$$\frac{3}{4}u-\frac{9}{4}=\frac{2}{3}u+\frac{-5}{3}$$

Ka taea te hautanga \frac{-5}{3} te tuhi anō ko -\frac{5}{3} mā te tango i te tohu tōraro.

$$\frac{3}{4}u-\frac{9}{4}=\frac{2}{3}u-\frac{5}{3}$$

Tangohia te \frac{2}{3}u mai i ngā taha e rua.

$$\frac{3}{4}u-\frac{9}{4}-\frac{2}{3}u=-\frac{5}{3}$$

Pahekotia te \frac{3}{4}u me -\frac{2}{3}u, ka \frac{1}{12}u.

$$\frac{1}{12}u-\frac{9}{4}=-\frac{5}{3}$$

Me tāpiri te \frac{9}{4} ki ngā taha e rua.

$$\frac{1}{12}u=-\frac{5}{3}+\frac{9}{4}$$

Ko te maha noa iti rawa atu o 3 me 4 ko 12. Me tahuri -\frac{5}{3} me \frac{9}{4} ki te hautau me te tautūnga 12.

$$\frac{1}{12}u=-\frac{20}{12}+\frac{27}{12}$$

Tā te mea he rite te tauraro o -\frac{20}{12} me \frac{27}{12}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$\frac{1}{12}u=\frac{-20+27}{12}$$

Tāpirihia te -20 ki te 27, ka 7.

$$\frac{1}{12}u=\frac{7}{12}$$

Me whakarea ngā taha e rua ki te 12, te tau utu o \frac{1}{12}.

$$u=\frac{7}{12}\times 12$$

Me whakakore te 12 me te 12.

$$u=7$$