Whakaoti i te 3/3div(3/2-1)+(1-0.6)*(-5/2)^2]div(-5/3)-20}div(-1)^30

$$\frac { 3 } { 3 } \div ( \frac { 3 } { 2 } - 1 ) + ( 1 - 0.6 ) \times ( - \frac { 5 } { 2 } ) ^ { 2 } ] \div ( - \frac { 5 } { 3 } ) - 20 \} \div ( - 1 ) ^ { 30 }$$

Aromātai

$$4.5$$

Ngā Upane Otinga

Whakawehea te 3 ki te 3, kia riro ko 1.

$$\frac{1}{\frac{3}{2}-1}+\left(1-0.6\right)\left(-\frac{5}{2}\right)^{2}$$

Me tahuri te 1 ki te hautau \frac{2}{2}.

$$\frac{1}{\frac{3}{2}-\frac{2}{2}}+\left(1-0.6\right)\left(-\frac{5}{2}\right)^{2}$$

Tā te mea he rite te tauraro o \frac{3}{2} me \frac{2}{2}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{1}{\frac{3-2}{2}}+\left(1-0.6\right)\left(-\frac{5}{2}\right)^{2}$$

Tangohia te 2 i te 3, ka 1.

$$\frac{1}{\frac{1}{2}}+\left(1-0.6\right)\left(-\frac{5}{2}\right)^{2}$$

Whakawehe 1 ki te \frac{1}{2} mā te whakarea 1 ki te tau huripoki o \frac{1}{2}.

$$1\times 2+\left(1-0.6\right)\left(-\frac{5}{2}\right)^{2}$$

Whakareatia te 1 ki te 2, ka 2.

$$2+\left(1-0.6\right)\left(-\frac{5}{2}\right)^{2}$$

Tangohia te 0.6 i te 1, ka 0.4.

$$2+0.4\left(-\frac{5}{2}\right)^{2}$$

Tātaihia te -\frac{5}{2} mā te pū o 2, kia riro ko \frac{25}{4}.

$$2+0.4\times \frac{25}{4}$$

Me tahuri ki tau ā-ira 0.4 ki te hautau \frac{4}{10}. Whakahekea te hautanga \frac{4}{10} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 2.

$$2+\frac{2}{5}\times \frac{25}{4}$$

Me whakarea te \frac{2}{5} ki te \frac{25}{4} mā te whakarea taurunga ki te taurunga me te tauraro ki te tauraro.

$$2+\frac{2\times 25}{5\times 4}$$

Mahia ngā whakarea i roto i te hautanga \frac{2\times 25}{5\times 4}.

$$2+\frac{50}{20}$$

Whakahekea te hautanga \frac{50}{20} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 10.

$$2+\frac{5}{2}$$

Me tahuri te 2 ki te hautau \frac{4}{2}.

$$\frac{4}{2}+\frac{5}{2}$$

Tā te mea he rite te tauraro o \frac{4}{2} me \frac{5}{2}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$\frac{4+5}{2}$$

Tāpirihia te 4 ki te 5, ka 9.

$$\frac{9}{2}$$

Tauwehe

$$\frac{3 ^ {2}}{2} = 4\frac{1}{2} = 4.5$$