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Whakaoti mō g
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Whakaoti mō x (complex solution)
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Whakaoti mō x
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Tohaina

\left(3x+2\right)\times 3-\left(2x+1\right)=2g\left(2x+1\right)\left(3x+2\right)
Me whakarea ngā taha e rua o te whārite ki te \left(2x+1\right)\left(3x+2\right), arā, te tauraro pātahi he tino iti rawa te kitea o 2x+1,3x+2.
9x+6-\left(2x+1\right)=2g\left(2x+1\right)\left(3x+2\right)
Whakamahia te āhuatanga tohatoha hei whakarea te 3x+2 ki te 3.
9x+6-2x-1=2g\left(2x+1\right)\left(3x+2\right)
Hei kimi i te tauaro o 2x+1, kimihia te tauaro o ia taurangi.
7x+6-1=2g\left(2x+1\right)\left(3x+2\right)
Pahekotia te 9x me -2x, ka 7x.
7x+5=2g\left(2x+1\right)\left(3x+2\right)
Tangohia te 1 i te 6, ka 5.
7x+5=\left(4xg+2g\right)\left(3x+2\right)
Whakamahia te āhuatanga tohatoha hei whakarea te 2g ki te 2x+1.
7x+5=12gx^{2}+14gx+4g
Whakamahia te āhuatanga tuaritanga hei whakarea te 4xg+2g ki te 3x+2 ka whakakotahi i ngā kupu rite.
12gx^{2}+14gx+4g=7x+5
Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.
\left(12x^{2}+14x+4\right)g=7x+5
Pahekotia ngā kīanga tau katoa e whai ana i te g.
\frac{\left(12x^{2}+14x+4\right)g}{12x^{2}+14x+4}=\frac{7x+5}{12x^{2}+14x+4}
Whakawehea ngā taha e rua ki te 12x^{2}+14x+4.
g=\frac{7x+5}{12x^{2}+14x+4}
Mā te whakawehe ki te 12x^{2}+14x+4 ka wetekia te whakareanga ki te 12x^{2}+14x+4.
g=\frac{7x+5}{2\left(6x^{2}+7x+2\right)}
Whakawehe 7x+5 ki te 12x^{2}+14x+4.