Whakaoti i te 3/2(y-5)+10=2y

$$\frac { 3 } { 2 } ( y - 5 ) + 10 = 2 y$$

Whakaoti mō y

$$y=5$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te \frac{3}{2} ki te y-5.

$$\frac{3}{2}y+\frac{3}{2}\left(-5\right)+10=2y$$

Tuhia te \frac{3}{2}\left(-5\right) hei hautanga kotahi.

$$\frac{3}{2}y+\frac{3\left(-5\right)}{2}+10=2y$$

Whakareatia te 3 ki te -5, ka -15.

$$\frac{3}{2}y+\frac{-15}{2}+10=2y$$

Ka taea te hautanga \frac{-15}{2} te tuhi anō ko -\frac{15}{2} mā te tango i te tohu tōraro.

$$\frac{3}{2}y-\frac{15}{2}+10=2y$$

Me tahuri te 10 ki te hautau \frac{20}{2}.

$$\frac{3}{2}y-\frac{15}{2}+\frac{20}{2}=2y$$

Tā te mea he rite te tauraro o -\frac{15}{2} me \frac{20}{2}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$\frac{3}{2}y+\frac{-15+20}{2}=2y$$

Tāpirihia te -15 ki te 20, ka 5.

$$\frac{3}{2}y+\frac{5}{2}=2y$$

Tangohia te 2y mai i ngā taha e rua.

$$\frac{3}{2}y+\frac{5}{2}-2y=0$$

Pahekotia te \frac{3}{2}y me -2y, ka -\frac{1}{2}y.

$$-\frac{1}{2}y+\frac{5}{2}=0$$

Tangohia te \frac{5}{2} mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$-\frac{1}{2}y=-\frac{5}{2}$$

Me whakarea ngā taha e rua ki te -2, te tau utu o -\frac{1}{2}.

$$y=-\frac{5}{2}\left(-2\right)$$

Tuhia te -\frac{5}{2}\left(-2\right) hei hautanga kotahi.

$$y=\frac{-5\left(-2\right)}{2}$$

Whakareatia te -5 ki te -2, ka 10.

$$y=\frac{10}{2}$$

Whakawehea te 10 ki te 2, kia riro ko 5.

$$y=5$$