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\frac{\left(3\sqrt{3}-2\right)\left(2\sqrt{7}-1\right)}{\left(2\sqrt{7}+1\right)\left(2\sqrt{7}-1\right)}
Whakangāwaritia te tauraro o \frac{3\sqrt{3}-2}{2\sqrt{7}+1} mā te whakarea i te taurunga me te tauraro ki te 2\sqrt{7}-1.
\frac{\left(3\sqrt{3}-2\right)\left(2\sqrt{7}-1\right)}{\left(2\sqrt{7}\right)^{2}-1^{2}}
Whakaarohia te \left(2\sqrt{7}+1\right)\left(2\sqrt{7}-1\right). Ka taea te whakareanga te panoni ki te rerekētanga o ngā pūrua mā te ture: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
\frac{\left(3\sqrt{3}-2\right)\left(2\sqrt{7}-1\right)}{2^{2}\left(\sqrt{7}\right)^{2}-1^{2}}
Whakarohaina te \left(2\sqrt{7}\right)^{2}.
\frac{\left(3\sqrt{3}-2\right)\left(2\sqrt{7}-1\right)}{4\left(\sqrt{7}\right)^{2}-1^{2}}
Tātaihia te 2 mā te pū o 2, kia riro ko 4.
\frac{\left(3\sqrt{3}-2\right)\left(2\sqrt{7}-1\right)}{4\times 7-1^{2}}
Ko te pūrua o \sqrt{7} ko 7.
\frac{\left(3\sqrt{3}-2\right)\left(2\sqrt{7}-1\right)}{28-1^{2}}
Whakareatia te 4 ki te 7, ka 28.
\frac{\left(3\sqrt{3}-2\right)\left(2\sqrt{7}-1\right)}{28-1}
Tātaihia te 1 mā te pū o 2, kia riro ko 1.
\frac{\left(3\sqrt{3}-2\right)\left(2\sqrt{7}-1\right)}{27}
Tangohia te 1 i te 28, ka 27.
\frac{6\sqrt{3}\sqrt{7}-3\sqrt{3}-4\sqrt{7}+2}{27}
Me hoatu te āhuatanga tohatoha mā te whakarea ia tau o 3\sqrt{3}-2 ki ia tau o 2\sqrt{7}-1.
\frac{6\sqrt{21}-3\sqrt{3}-4\sqrt{7}+2}{27}
Hei whakarea \sqrt{3} me \sqrt{7}, whakareatia ngā tau i raro i te pūtake rua.