Whakaoti i te frac{24x(x^{3}+1)^{3/2}-3x^{2}(72x^{2}(x^3+1)^frac{1{2}})}{16(x^3+1)^3/2}

$$\frac { 24 x ( x ^ { 3 } + 1 ) ^ { 3 / 2 } - 3 x ^ { 2 } ( 72 x ^ { 2 } ( x ^ { 3 } + 1 ) ^ { \frac { 1 } { 2 } } ) } { 16 ( x ^ { 3 } + 1 ) ^ { 3 / 2 } }$$

Aromātai

$$-\frac{3x\left(8x^{3}-1\right)}{2\left(x^{3}+1\right)}$$

Ngā Hipanga Rongoā Poto

Hei whakarea i ngā pū o te pūtake kotahi, me tāpiri ō rātou taupū. Tāpiria te 2 me te 2 kia riro ai te 4.

$$\frac{24x\left(x^{3}+1\right)^{\frac{3}{2}}-3x^{4}\times 72\left(x^{3}+1\right)^{\frac{1}{2}}}{16\left(x^{3}+1\right)^{\frac{3}{2}}}$$

Whakareatia te 3 ki te 72, ka 216.

$$\frac{24x\left(x^{3}+1\right)^{\frac{3}{2}}-216x^{4}\left(x^{3}+1\right)^{\frac{1}{2}}}{16\left(x^{3}+1\right)^{\frac{3}{2}}}$$

Me whakatauwehe ngā kīanga kāore anō i whakatauwehea.

$$\frac{24x\left(2x-1\right)\sqrt{x^{3}+1}\left(-4x^{2}-2x-1\right)}{16\left(x^{3}+1\right)^{\frac{3}{2}}}$$

Me whakakore tahi te 8\sqrt{x^{3}+1} i te taurunga me te tauraro.

$$\frac{3x\left(2x-1\right)\left(-4x^{2}-2x-1\right)}{2\left(x^{3}+1\right)}$$

Me whakaroha te kīanga.

$$\frac{-24x^{4}+3x}{2x^{3}+2}$$

Tauwehe

$$-\frac{3x\left(2x-1\right)\left(4x^{2}+2x+1\right)}{2\left(x+1\right)\left(x^{2}-x+1\right)}$$