Whakaoti i te 23/24x+1/3=4+1/6

$$\frac { 23 } { 24 } x + \frac { 1 } { 3 } = 4 + \frac { 1 } { 6 }$$

Whakaoti mō x

$$x=4$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Me tahuri te 4 ki te hautau \frac{24}{6}.

$$\frac{23}{24}x+\frac{1}{3}=\frac{24}{6}+\frac{1}{6}$$

Tā te mea he rite te tauraro o \frac{24}{6} me \frac{1}{6}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$\frac{23}{24}x+\frac{1}{3}=\frac{24+1}{6}$$

Tāpirihia te 24 ki te 1, ka 25.

$$\frac{23}{24}x+\frac{1}{3}=\frac{25}{6}$$

Tangohia te \frac{1}{3} mai i ngā taha e rua.

$$\frac{23}{24}x=\frac{25}{6}-\frac{1}{3}$$

Ko te maha noa iti rawa atu o 6 me 3 ko 6. Me tahuri \frac{25}{6} me \frac{1}{3} ki te hautau me te tautūnga 6.

$$\frac{23}{24}x=\frac{25}{6}-\frac{2}{6}$$

Tā te mea he rite te tauraro o \frac{25}{6} me \frac{2}{6}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{23}{24}x=\frac{25-2}{6}$$

Tangohia te 2 i te 25, ka 23.

$$\frac{23}{24}x=\frac{23}{6}$$

Me whakarea ngā taha e rua ki te \frac{24}{23}, te tau utu o \frac{23}{24}.

$$x=\frac{23}{6}\times \frac{24}{23}$$

Me whakarea te \frac{23}{6} ki te \frac{24}{23} mā te whakarea taurunga ki te taurunga me te tauraro ki te tauraro.

$$x=\frac{23\times 24}{6\times 23}$$

Me whakakore tahi te 23 i te taurunga me te tauraro.

$$x=\frac{24}{6}$$

Whakawehea te 24 ki te 6, kia riro ko 4.

$$x=4$$