Whakaoti i te 20x^6y^4/5x^2y

$$\frac { 20 x ^ { 6 } y ^ { 4 } } { 5 x ^ { 2 } y }$$

Aromātai

$$4y^{3}x^{4}$$

Ngā Upane e Whakamahi ana i te Āhuatanga o te Otinga o ngā Pū

Whakamahia ngā ture taupū hei whakarūnā i te kīanga.

$$\frac{20^{1}x^{6}y^{4}}{5^{1}x^{2}y^{1}}$$

Hei whakawehe i ngā pū o te pūtake kotahi, tangohia te taupū o te tauraro mai i te taupū o te taurunga.

$$\frac{20^{1}}{5^{1}}x^{6-2}y^{4-1}$$

Tango 2 mai i 6.

$$\frac{20^{1}}{5^{1}}x^{4}y^{4-1}$$

Tango 1 mai i 4.

$$\frac{20^{1}}{5^{1}}x^{4}y^{3}$$

Whakawehe 20 ki te 5.

$$4x^{4}y^{3}$$

Kimi Pārōnaki e ai ki x

$$16\left(xy\right)^{3}$$

Ngā Upane Otinga

Hei whakawehe i ngā pū o te pūtake kotahi, tangohia te taupū o te tauraro mai i te taupū o te taurunga.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{20y^{4}}{5y}x^{6-2})$$

Mahia ngā tātaitanga.

$$\frac{\mathrm{d}}{\mathrm{d}x}(4y^{3}x^{4})$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$4\times 4y^{3}x^{4-1}$$

Mahia ngā tātaitanga.

$$16y^{3}x^{3}$$