Whakaoti i te 2x-6/3x-8=2x-5/3x-7

$$\frac { 2 x - 6 } { 3 x - 8 } = \frac { 2 x - 5 } { 3 x - 7 }$$

Whakaoti mō x

$$x=2$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tē taea kia ōrite te tāupe x ki tētahi o ngā uara \frac{7}{3},\frac{8}{3} nā te kore tautuhi i te whakawehenga mā te kore. Me whakarea ngā taha e rua o te whārite ki te \left(3x-8\right)\left(3x-7\right), arā, te tauraro pātahi he tino iti rawa te kitea o 3x-8,3x-7.

$$\left(3x-7\right)\left(2x-6\right)=\left(3x-8\right)\left(2x-5\right)$$

Whakamahia te āhuatanga tuaritanga hei whakarea te 3x-7 ki te 2x-6 ka whakakotahi i ngā kupu rite.

$$6x^{2}-32x+42=\left(3x-8\right)\left(2x-5\right)$$

Whakamahia te āhuatanga tuaritanga hei whakarea te 3x-8 ki te 2x-5 ka whakakotahi i ngā kupu rite.

$$6x^{2}-32x+42=6x^{2}-31x+40$$

Tangohia te 6x^{2} mai i ngā taha e rua.

$$6x^{2}-32x+42-6x^{2}=-31x+40$$

Pahekotia te 6x^{2} me -6x^{2}, ka 0.

$$-32x+42=-31x+40$$

Me tāpiri te 31x ki ngā taha e rua.

$$-32x+42+31x=40$$

Pahekotia te -32x me 31x, ka -x.

$$-x+42=40$$

Tangohia te 42 mai i ngā taha e rua.

$$-x=40-42$$

Tangohia te 42 i te 40, ka -2.

$$-x=-2$$

Me whakarea ngā taha e rua ki te -1.

$$x=2$$