Whakaoti i te 2x-3/x+1*2x-5/x-1=

$$\frac { 2 x - 3 } { x + 1 } \times \frac { 2 x - 5 } { x - 1 } =$$

Aromātai

$$\frac{\left(2x-5\right)\left(2x-3\right)}{x^{2}-1}$$

Ngā Hipanga Rongoā Poto

Me whakarea te \frac{2x-3}{x+1} ki te \frac{2x-5}{x-1} mā te whakarea taurunga ki te taurunga me te tauraro ki te tauraro.

$$\frac{\left(2x-3\right)\left(2x-5\right)}{\left(x+1\right)\left(x-1\right)}$$

Me hoatu te āhuatanga tohatoha mā te whakarea ia tau o 2x-3 ki ia tau o 2x-5.

$$\frac{4x^{2}-10x-6x+15}{\left(x+1\right)\left(x-1\right)}$$

Pahekotia te -10x me -6x, ka -16x.

$$\frac{4x^{2}-16x+15}{\left(x+1\right)\left(x-1\right)}$$

Whakaarohia te \left(x+1\right)\left(x-1\right). Ka taea te whakareanga te panoni ki te rerekētanga o ngā pūrua mā te ture: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$\frac{4x^{2}-16x+15}{x^{2}-1^{2}}$$

Tātaihia te 1 mā te pū o 2, kia riro ko 1.

$$\frac{4x^{2}-16x+15}{x^{2}-1}$$

Whakaroha

$$\frac{4x^{2}-16x+15}{x^{2}-1}$$

Ngā Hipanga Rongoā Poto

Me whakarea te \frac{2x-3}{x+1} ki te \frac{2x-5}{x-1} mā te whakarea taurunga ki te taurunga me te tauraro ki te tauraro.

$$\frac{\left(2x-3\right)\left(2x-5\right)}{\left(x+1\right)\left(x-1\right)}$$

Me hoatu te āhuatanga tohatoha mā te whakarea ia tau o 2x-3 ki ia tau o 2x-5.

$$\frac{4x^{2}-10x-6x+15}{\left(x+1\right)\left(x-1\right)}$$

Pahekotia te -10x me -6x, ka -16x.

$$\frac{4x^{2}-16x+15}{\left(x+1\right)\left(x-1\right)}$$

Whakaarohia te \left(x+1\right)\left(x-1\right). Ka taea te whakareanga te panoni ki te rerekētanga o ngā pūrua mā te ture: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$\frac{4x^{2}-16x+15}{x^{2}-1^{2}}$$

Tātaihia te 1 mā te pū o 2, kia riro ko 1.

$$\frac{4x^{2}-16x+15}{x^{2}-1}$$