Whakaoti mō x
x\geq \frac{1}{5}
Graph
Pātaitai
Algebra
5 raruraru e ōrite ana ki:
\frac { 2 x - 1 } { 2 } - \frac { 5 x + 2 } { 6 } - x \leq - 1
Tohaina
Kua tāruatia ki te papatopenga
3\left(2x-1\right)-\left(5x+2\right)-6x\leq -6
Me whakarea ngā taha e rua o te whārite ki te 6, arā, te tauraro pātahi he tino iti rawa te kitea o 2,6. I te mea he tōrunga te 6, kāore e huri te ahunga koreōrite.
6x-3-\left(5x+2\right)-6x\leq -6
Whakamahia te āhuatanga tohatoha hei whakarea te 3 ki te 2x-1.
6x-3-5x-2-6x\leq -6
Hei kimi i te tauaro o 5x+2, kimihia te tauaro o ia taurangi.
x-3-2-6x\leq -6
Pahekotia te 6x me -5x, ka x.
x-5-6x\leq -6
Tangohia te 2 i te -3, ka -5.
-5x-5\leq -6
Pahekotia te x me -6x, ka -5x.
-5x\leq -6+5
Me tāpiri te 5 ki ngā taha e rua.
-5x\leq -1
Tāpirihia te -6 ki te 5, ka -1.
x\geq \frac{-1}{-5}
Whakawehea ngā taha e rua ki te -5. I te mea he tōraro a -5, ka huri te ahunga koreōrite.
x\geq \frac{1}{5}
Ka taea te hautanga \frac{-1}{-5} te whakamāmā ki te \frac{1}{5} mā te tango tahi i te tohu tōraro i te taurunga me te tauraro.
Ngā Tauira
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{ x } ^ { 2 } - 4 x - 5 = 0
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