Aromātai
\frac{2x^{2}+5x+1}{\left(x+1\right)\left(2x+1\right)\left(3x+1\right)}
Whakaroha
\frac{2x^{2}+5x+1}{6x^{3}+11x^{2}+6x+1}
Graph
Tohaina
Kua tāruatia ki te papatopenga
\frac{2\left(x-\left(-\frac{1}{4}\sqrt{17}-\frac{5}{4}\right)\right)\left(x-\left(\frac{1}{4}\sqrt{17}-\frac{5}{4}\right)\right)\left(x^{2}+x+1\right)}{\left(x+1\right)\left(2x+1\right)\left(3x+1\right)\left(x^{2}+x+1\right)}
Me whakatauwehe ngā kīanga kāore anō i whakatauwehea.
\frac{2\left(x-\left(-\frac{1}{4}\sqrt{17}-\frac{5}{4}\right)\right)\left(x-\left(\frac{1}{4}\sqrt{17}-\frac{5}{4}\right)\right)}{\left(x+1\right)\left(2x+1\right)\left(3x+1\right)}
Me whakakore tahi te x^{2}+x+1 i te taurunga me te tauraro.
\frac{2x^{2}+5x+1}{6x^{3}+11x^{2}+6x+1}
Me whakaroha te kīanga.
\frac{2\left(x-\left(-\frac{1}{4}\sqrt{17}-\frac{5}{4}\right)\right)\left(x-\left(\frac{1}{4}\sqrt{17}-\frac{5}{4}\right)\right)\left(x^{2}+x+1\right)}{\left(x+1\right)\left(2x+1\right)\left(3x+1\right)\left(x^{2}+x+1\right)}
Me whakatauwehe ngā kīanga kāore anō i whakatauwehea.
\frac{2\left(x-\left(-\frac{1}{4}\sqrt{17}-\frac{5}{4}\right)\right)\left(x-\left(\frac{1}{4}\sqrt{17}-\frac{5}{4}\right)\right)}{\left(x+1\right)\left(2x+1\right)\left(3x+1\right)}
Me whakakore tahi te x^{2}+x+1 i te taurunga me te tauraro.
\frac{2x^{2}+5x+1}{6x^{3}+11x^{2}+6x+1}
Me whakaroha te kīanga.
Ngā Tauira
whārite tapawhā
{ x } ^ { 2 } - 4 x - 5 = 0
Āhuahanga
4 \sin \theta \cos \theta = 2 \sin \theta
whārite paerangi
y = 3x + 4
Arithmetic
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Poukapa
\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
whārite Simultaneous
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Whakarerekētanga
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Whakaurunga
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Ngā Tepe
\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}