Whakaoti i te 2x^3/-8x^4

$$\frac { 2 x ^ { 3 } } { - 8 x ^ { 4 } }$$

Aromātai

$$-\frac{1}{4x}$$

Ngā Upane mō te Hua o ngā Pānga Taupū e Rua

Whakamahia ngā ture taupū hei whakarūnā i te kīanga.

$$\left(2x^{3}\right)^{1}\times \frac{1}{-8x^{4}}$$

Hei hiki i te hua o ngā tau e rua, neke atu rānei ki tētahi pū, hīkina ia tau ki te pū ka tuhi ko tāna hua.

$$2^{1}\left(x^{3}\right)^{1}\times \frac{1}{-8}\times \frac{1}{x^{4}}$$

Whakamahia te Āhuatanga Kōaro o te Whakareanga.

$$2^{1}\times \frac{1}{-8}\left(x^{3}\right)^{1}\times \frac{1}{x^{4}}$$

Hei hiki pū ki tētahi pū anō, me whakarea ngā taupū.

$$2^{1}\times \frac{1}{-8}x^{3}x^{4\left(-1\right)}$$

Whakareatia 4 ki te -1.

$$2^{1}\times \frac{1}{-8}x^{3}x^{-4}$$

Hei whakarea pū o te pūtake ōrite, tāpiri ana taupū.

$$2^{1}\times \frac{1}{-8}x^{3-4}$$

Tāpirihia ngā taupū 3 me -4.

$$2^{1}\times \frac{1}{-8}\times \frac{1}{x}$$

Hīkina te 2 ki te pū 1.

$$2\times \frac{1}{-8}\times \frac{1}{x}$$

Hīkina te -8 ki te pū -1.

$$2\left(-\frac{1}{8}\right)\times \frac{1}{x}$$

Whakareatia 2 ki te -\frac{1}{8}.

$$-\frac{1}{4}\times \frac{1}{x}$$

Ngā Upane mō te Otinga o ngā Pānga Taupū

Whakamahia ngā ture taupū hei whakarūnā i te kīanga.

$$\frac{2^{1}x^{3}}{\left(-8\right)^{1}x^{4}}$$

Hei whakawehe i ngā pū o te pūtake kotahi, tangohia te taupū o te tauraro mai i te taupū o te taurunga.

$$\frac{2^{1}x^{3-4}}{\left(-8\right)^{1}}$$

Tango 4 mai i 3.

$$\frac{2^{1}\times \frac{1}{x}}{\left(-8\right)^{1}}$$

Whakahekea te hautanga \frac{2}{-8} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 2.

$$-\frac{1}{4}\times \frac{1}{x}$$

Kimi Pārōnaki e ai ki x

$$\frac{1}{4x^{2}}$$

Ngā Upane Otinga

Hei whakawehe i ngā pū o te pūtake kotahi, tangohia te taupū o te tauraro mai i te taupū o te taurunga.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{2}{-8}x^{3-4})$$

Mahia ngā tātaitanga.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-\frac{1}{4}\times \frac{1}{x})$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$-\left(-\frac{1}{4}\right)x^{-1-1}$$

Mahia ngā tātaitanga.

$$\frac{1}{4}x^{-2}$$