Whakaoti i te frac{2x^{2}-5x+3}{x^{6}y^3}*x^4y^4/2x^2-x-3

$$\frac { 2 x ^ { 2 } - 5 x + 3 } { x ^ { 6 } y ^ { 3 } } \cdot \frac { x ^ { 4 } y ^ { 4 } } { 2 x ^ { 2 } - x - 3 }$$

Aromātai

$$\frac{y\left(x-1\right)}{\left(x+1\right)x^{2}}$$

Ngā Hipanga Rongoā Poto

Me whakarea te \frac{2x^{2}-5x+3}{x^{6}y^{3}} ki te \frac{x^{4}y^{4}}{2x^{2}-x-3} mā te whakarea taurunga ki te taurunga me te tauraro ki te tauraro.

$$\frac{\left(2x^{2}-5x+3\right)x^{4}y^{4}}{x^{6}y^{3}\left(2x^{2}-x-3\right)}$$

Me whakakore tahi te y^{3}x^{4} i te taurunga me te tauraro.

$$\frac{y\left(2x^{2}-5x+3\right)}{x^{2}\left(2x^{2}-x-3\right)}$$

Me whakatauwehe ngā kīanga kāore anō i whakatauwehea.

$$\frac{y\left(x-1\right)\left(2x-3\right)}{\left(2x-3\right)\left(x+1\right)x^{2}}$$

Me whakakore tahi te 2x-3 i te taurunga me te tauraro.

$$\frac{y\left(x-1\right)}{\left(x+1\right)x^{2}}$$

Me whakaroha te kīanga.

$$\frac{xy-y}{x^{3}+x^{2}}$$

Whakaroha

$$\frac{xy-y}{\left(x+1\right)x^{2}}$$

Ngā Hipanga Rongoā Poto

Me whakarea te \frac{2x^{2}-5x+3}{x^{6}y^{3}} ki te \frac{x^{4}y^{4}}{2x^{2}-x-3} mā te whakarea taurunga ki te taurunga me te tauraro ki te tauraro.

$$\frac{\left(2x^{2}-5x+3\right)x^{4}y^{4}}{x^{6}y^{3}\left(2x^{2}-x-3\right)}$$

Me whakakore tahi te y^{3}x^{4} i te taurunga me te tauraro.

$$\frac{y\left(2x^{2}-5x+3\right)}{x^{2}\left(2x^{2}-x-3\right)}$$

Me whakatauwehe ngā kīanga kāore anō i whakatauwehea.

$$\frac{y\left(x-1\right)\left(2x-3\right)}{\left(2x-3\right)\left(x+1\right)x^{2}}$$

Me whakakore tahi te 2x-3 i te taurunga me te tauraro.

$$\frac{y\left(x-1\right)}{\left(x+1\right)x^{2}}$$

Me whakaroha te kīanga.

$$\frac{xy-y}{x^{3}+x^{2}}$$