Whakaoti i te 2-x/x+1+x+8/x-2-4x/x^2-x-2

$$\frac { 2 - x } { x + 1 } + \frac { x + 8 } { x - 2 } - \frac { 4 x } { x ^ { 2 } - x - 2 }$$

Aromātai

$$\frac{9x+4}{\left(x-2\right)\left(x+1\right)}$$

Ngā Hipanga Rongoā Poto

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Ko te taurea pātahi iti rawa o x+1 me x-2 ko \left(x-2\right)\left(x+1\right). Whakareatia \frac{2-x}{x+1} ki te \frac{x-2}{x-2}. Whakareatia \frac{x+8}{x-2} ki te \frac{x+1}{x+1}.

$$\frac{\left(2-x\right)\left(x-2\right)}{\left(x-2\right)\left(x+1\right)}+\frac{\left(x+8\right)\left(x+1\right)}{\left(x-2\right)\left(x+1\right)}-\frac{4x}{x^{2}-x-2}$$

Tā te mea he rite te tauraro o \frac{\left(2-x\right)\left(x-2\right)}{\left(x-2\right)\left(x+1\right)} me \frac{\left(x+8\right)\left(x+1\right)}{\left(x-2\right)\left(x+1\right)}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$\frac{\left(2-x\right)\left(x-2\right)+\left(x+8\right)\left(x+1\right)}{\left(x-2\right)\left(x+1\right)}-\frac{4x}{x^{2}-x-2}$$

Mahia ngā whakarea i roto o \left(2-x\right)\left(x-2\right)+\left(x+8\right)\left(x+1\right).

$$\frac{2x-4-x^{2}+2x+x^{2}+x+8x+8}{\left(x-2\right)\left(x+1\right)}-\frac{4x}{x^{2}-x-2}$$

Whakakotahitia ngā kupu rite i 2x-4-x^{2}+2x+x^{2}+x+8x+8.

$$\frac{13x+4}{\left(x-2\right)\left(x+1\right)}-\frac{4x}{x^{2}-x-2}$$

Tauwehea te x^{2}-x-2.

$$\frac{13x+4}{\left(x-2\right)\left(x+1\right)}-\frac{4x}{\left(x-2\right)\left(x+1\right)}$$

Tā te mea he rite te tauraro o \frac{13x+4}{\left(x-2\right)\left(x+1\right)} me \frac{4x}{\left(x-2\right)\left(x+1\right)}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{13x+4-4x}{\left(x-2\right)\left(x+1\right)}$$

Whakakotahitia ngā kupu rite i 13x+4-4x.

$$\frac{9x+4}{\left(x-2\right)\left(x+1\right)}$$

Whakarohaina te \left(x-2\right)\left(x+1\right).

$$\frac{9x+4}{x^{2}-x-2}$$

Whakaroha

$$\frac{9x+4}{\left(x-2\right)\left(x+1\right)}$$

Ngā Hipanga Rongoā Poto

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Ko te taurea pātahi iti rawa o x+1 me x-2 ko \left(x-2\right)\left(x+1\right). Whakareatia \frac{2-x}{x+1} ki te \frac{x-2}{x-2}. Whakareatia \frac{x+8}{x-2} ki te \frac{x+1}{x+1}.

$$\frac{\left(2-x\right)\left(x-2\right)}{\left(x-2\right)\left(x+1\right)}+\frac{\left(x+8\right)\left(x+1\right)}{\left(x-2\right)\left(x+1\right)}-\frac{4x}{x^{2}-x-2}$$

Tā te mea he rite te tauraro o \frac{\left(2-x\right)\left(x-2\right)}{\left(x-2\right)\left(x+1\right)} me \frac{\left(x+8\right)\left(x+1\right)}{\left(x-2\right)\left(x+1\right)}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$\frac{\left(2-x\right)\left(x-2\right)+\left(x+8\right)\left(x+1\right)}{\left(x-2\right)\left(x+1\right)}-\frac{4x}{x^{2}-x-2}$$

Mahia ngā whakarea i roto o \left(2-x\right)\left(x-2\right)+\left(x+8\right)\left(x+1\right).

$$\frac{2x-4-x^{2}+2x+x^{2}+x+8x+8}{\left(x-2\right)\left(x+1\right)}-\frac{4x}{x^{2}-x-2}$$

Whakakotahitia ngā kupu rite i 2x-4-x^{2}+2x+x^{2}+x+8x+8.

$$\frac{13x+4}{\left(x-2\right)\left(x+1\right)}-\frac{4x}{x^{2}-x-2}$$

Tauwehea te x^{2}-x-2.

$$\frac{13x+4}{\left(x-2\right)\left(x+1\right)}-\frac{4x}{\left(x-2\right)\left(x+1\right)}$$

Tā te mea he rite te tauraro o \frac{13x+4}{\left(x-2\right)\left(x+1\right)} me \frac{4x}{\left(x-2\right)\left(x+1\right)}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{13x+4-4x}{\left(x-2\right)\left(x+1\right)}$$

Whakakotahitia ngā kupu rite i 13x+4-4x.

$$\frac{9x+4}{\left(x-2\right)\left(x+1\right)}$$

Whakarohaina te \left(x-2\right)\left(x+1\right).

$$\frac{9x+4}{x^{2}-x-2}$$