Whakaoti i te 2-i/4+3i

$$\frac { 2 - i } { 4 + 3 i }$$

Aromātai

$$\frac{1}{5}-\frac{2}{5}i=0.2-0.4i$$

Ngā Upane Otinga

Whakareatia te taurunga me te tauraro ki te haumi hiato o te tauraro, 4-3i.

$$\frac{\left(2-i\right)\left(4-3i\right)}{\left(4+3i\right)\left(4-3i\right)}$$

Ka taea te whakareanga te panoni ki te rerekētanga o ngā pūrua mā te ture: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$\frac{\left(2-i\right)\left(4-3i\right)}{4^{2}-3^{2}i^{2}}$$

Hei tōna tikanga, ko te i^{2} ko -1. Tātaitia te tauraro.

$$\frac{\left(2-i\right)\left(4-3i\right)}{25}$$

Me whakarea ngā tau matatini 2-i me 4-3i pēnā i te whakarea huarua.

$$\frac{2\times 4+2\times \left(-3i\right)-i\times 4-\left(-3i^{2}\right)}{25}$$

Hei tōna tikanga, ko te i^{2} ko -1.

$$\frac{2\times 4+2\times \left(-3i\right)-i\times 4-\left(-3\left(-1\right)\right)}{25}$$

Mahia ngā whakarea i roto o 2\times 4+2\times \left(-3i\right)-i\times 4-\left(-3\left(-1\right)\right).

$$\frac{8-6i-4i-3}{25}$$

Whakakotahitia ngā wāhi tūturu me ngā wāhi pōhewa ki 8-6i-4i-3.

$$\frac{8-3+\left(-6-4\right)i}{25}$$

Mahia ngā tāpiri i roto o 8-3+\left(-6-4\right)i.

$$\frac{5-10i}{25}$$

Whakawehea te 5-10i ki te 25, kia riro ko \frac{1}{5}-\frac{2}{5}i.

$$\frac{1}{5}-\frac{2}{5}i$$

Wāhi Tūturu

$$\frac{1}{5} = 0.2$$

Ngā Upane Otinga

Me whakarea te taurunga me te tauraro o \frac{2-i}{4+3i} ki te haumi hiato o te tauraro, 4-3i.

$$Re(\frac{\left(2-i\right)\left(4-3i\right)}{\left(4+3i\right)\left(4-3i\right)})$$

Ka taea te whakareanga te panoni ki te rerekētanga o ngā pūrua mā te ture: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$Re(\frac{\left(2-i\right)\left(4-3i\right)}{4^{2}-3^{2}i^{2}})$$

Hei tōna tikanga, ko te i^{2} ko -1. Tātaitia te tauraro.

$$Re(\frac{\left(2-i\right)\left(4-3i\right)}{25})$$

Me whakarea ngā tau matatini 2-i me 4-3i pēnā i te whakarea huarua.

$$Re(\frac{2\times 4+2\times \left(-3i\right)-i\times 4-\left(-3i^{2}\right)}{25})$$

Hei tōna tikanga, ko te i^{2} ko -1.

$$Re(\frac{2\times 4+2\times \left(-3i\right)-i\times 4-\left(-3\left(-1\right)\right)}{25})$$

Mahia ngā whakarea i roto o 2\times 4+2\times \left(-3i\right)-i\times 4-\left(-3\left(-1\right)\right).

$$Re(\frac{8-6i-4i-3}{25})$$

Whakakotahitia ngā wāhi tūturu me ngā wāhi pōhewa ki 8-6i-4i-3.

$$Re(\frac{8-3+\left(-6-4\right)i}{25})$$

Mahia ngā tāpiri i roto o 8-3+\left(-6-4\right)i.

$$Re(\frac{5-10i}{25})$$

Whakawehea te 5-10i ki te 25, kia riro ko \frac{1}{5}-\frac{2}{5}i.

$$Re(\frac{1}{5}-\frac{2}{5}i)$$

Ko te wāhi tūturu o \frac{1}{5}-\frac{2}{5}i ko \frac{1}{5}.

$$\frac{1}{5}$$