Whakaoti i te 2-i/3+i

$$\frac { 2 - i } { 3 + i }$$

Aromātai

$$\frac{1}{2}-\frac{1}{2}i=0.5-0.5i$$

Ngā Upane Otinga

Whakareatia te taurunga me te tauraro ki te haumi hiato o te tauraro, 3-i.

$$\frac{\left(2-i\right)\left(3-i\right)}{\left(3+i\right)\left(3-i\right)}$$

Ka taea te whakareanga te panoni ki te rerekētanga o ngā pūrua mā te ture: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$\frac{\left(2-i\right)\left(3-i\right)}{3^{2}-i^{2}}$$

Hei tōna tikanga, ko te i^{2} ko -1. Tātaitia te tauraro.

$$\frac{\left(2-i\right)\left(3-i\right)}{10}$$

Me whakarea ngā tau matatini 2-i me 3-i pēnā i te whakarea huarua.

$$\frac{2\times 3+2\left(-i\right)-i\times 3-\left(-i^{2}\right)}{10}$$

Hei tōna tikanga, ko te i^{2} ko -1.

$$\frac{2\times 3+2\left(-i\right)-i\times 3-\left(-\left(-1\right)\right)}{10}$$

Mahia ngā whakarea i roto o 2\times 3+2\left(-i\right)-i\times 3-\left(-\left(-1\right)\right).

$$\frac{6-2i-3i-1}{10}$$

Whakakotahitia ngā wāhi tūturu me ngā wāhi pōhewa ki 6-2i-3i-1.

$$\frac{6-1+\left(-2-3\right)i}{10}$$

Mahia ngā tāpiri i roto o 6-1+\left(-2-3\right)i.

$$\frac{5-5i}{10}$$

Whakawehea te 5-5i ki te 10, kia riro ko \frac{1}{2}-\frac{1}{2}i.

$$\frac{1}{2}-\frac{1}{2}i$$

Wāhi Tūturu

$$\frac{1}{2} = 0.5$$

Ngā Upane Otinga

Me whakarea te taurunga me te tauraro o \frac{2-i}{3+i} ki te haumi hiato o te tauraro, 3-i.

$$Re(\frac{\left(2-i\right)\left(3-i\right)}{\left(3+i\right)\left(3-i\right)})$$

Ka taea te whakareanga te panoni ki te rerekētanga o ngā pūrua mā te ture: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$Re(\frac{\left(2-i\right)\left(3-i\right)}{3^{2}-i^{2}})$$

Hei tōna tikanga, ko te i^{2} ko -1. Tātaitia te tauraro.

$$Re(\frac{\left(2-i\right)\left(3-i\right)}{10})$$

Me whakarea ngā tau matatini 2-i me 3-i pēnā i te whakarea huarua.

$$Re(\frac{2\times 3+2\left(-i\right)-i\times 3-\left(-i^{2}\right)}{10})$$

Hei tōna tikanga, ko te i^{2} ko -1.

$$Re(\frac{2\times 3+2\left(-i\right)-i\times 3-\left(-\left(-1\right)\right)}{10})$$

Mahia ngā whakarea i roto o 2\times 3+2\left(-i\right)-i\times 3-\left(-\left(-1\right)\right).

$$Re(\frac{6-2i-3i-1}{10})$$

Whakakotahitia ngā wāhi tūturu me ngā wāhi pōhewa ki 6-2i-3i-1.

$$Re(\frac{6-1+\left(-2-3\right)i}{10})$$

Mahia ngā tāpiri i roto o 6-1+\left(-2-3\right)i.

$$Re(\frac{5-5i}{10})$$

Whakawehea te 5-5i ki te 10, kia riro ko \frac{1}{2}-\frac{1}{2}i.

$$Re(\frac{1}{2}-\frac{1}{2}i)$$

Ko te wāhi tūturu o \frac{1}{2}-\frac{1}{2}i ko \frac{1}{2}.

$$\frac{1}{2}$$