Whakaoti i te 2(x+1)/3=5(x+1)/6-1

$$\frac { 2 ( x + 1 ) } { 3 } = \frac { 5 ( x + 1 ) } { 6 } - 1$$

Whakaoti mō x

$$x=5$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Me whakarea ngā taha e rua o te whārite ki te 6, arā, te tauraro pātahi he tino iti rawa te kitea o 3,6.

$$2\times 2\left(x+1\right)=5\left(x+1\right)-6$$

Whakareatia te 2 ki te 2, ka 4.

$$4\left(x+1\right)=5\left(x+1\right)-6$$

Whakamahia te āhuatanga tohatoha hei whakarea te 4 ki te x+1.

$$4x+4=5\left(x+1\right)-6$$

Whakamahia te āhuatanga tohatoha hei whakarea te 5 ki te x+1.

$$4x+4=5x+5-6$$

Tangohia te 6 i te 5, ka -1.

$$4x+4=5x-1$$

Tangohia te 5x mai i ngā taha e rua.

$$4x+4-5x=-1$$

Pahekotia te 4x me -5x, ka -x.

$$-x+4=-1$$

Tangohia te 4 mai i ngā taha e rua.

$$-x=-1-4$$

Tangohia te 4 i te -1, ka -5.

$$-x=-5$$

Me whakarea ngā taha e rua ki te -1.

$$x=5$$