Whakaoti i te 2/x^2-9+5/x-3=3/x+3

$$\frac { 2 } { x ^ { 2 } - 9 } + \frac { 5 } { x - 3 } = \frac { 3 } { x + 3 }$$

Whakaoti mō x

$$x=-13$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tē taea kia ōrite te tāupe x ki tētahi o ngā uara -3,3 nā te kore tautuhi i te whakawehenga mā te kore. Me whakarea ngā taha e rua o te whārite ki te \left(x-3\right)\left(x+3\right), arā, te tauraro pātahi he tino iti rawa te kitea o x^{2}-9,x-3,x+3.

$$2+\left(x+3\right)\times 5=\left(x-3\right)\times 3$$

Whakamahia te āhuatanga tohatoha hei whakarea te x+3 ki te 5.

$$2+5x+15=\left(x-3\right)\times 3$$

Tāpirihia te 2 ki te 15, ka 17.

$$17+5x=\left(x-3\right)\times 3$$

Whakamahia te āhuatanga tohatoha hei whakarea te x-3 ki te 3.

$$17+5x=3x-9$$

Tangohia te 3x mai i ngā taha e rua.

$$17+5x-3x=-9$$

Pahekotia te 5x me -3x, ka 2x.

$$17+2x=-9$$

Tangohia te 17 mai i ngā taha e rua.

$$2x=-9-17$$

Tangohia te 17 i te -9, ka -26.

$$2x=-26$$

Whakawehea ngā taha e rua ki te 2.

$$x=\frac{-26}{2}$$

Whakawehea te -26 ki te 2, kia riro ko -13.

$$x=-13$$