Whakaoti i te 2/3a-1/3b=2

$$\frac { 2 } { 3 } a - \frac { 1 } { 3 } b = 2$$

Whakaoti mō a

$$a=\frac{b+6}{2}$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Me tāpiri te \frac{1}{3}b ki ngā taha e rua.

$$\frac{2}{3}a=2+\frac{1}{3}b$$

He hanga arowhānui tō te whārite.

$$\frac{2}{3}a=\frac{b}{3}+2$$

Whakawehea ngā taha e rua o te whārite ki te \frac{2}{3}, he ōrite ki te whakarea i ngā taha e rua ki te tau huripoki o te hautanga.

$$\frac{\frac{2}{3}a}{\frac{2}{3}}=\frac{\frac{b}{3}+2}{\frac{2}{3}}$$

Mā te whakawehe ki te \frac{2}{3} ka wetekia te whakareanga ki te \frac{2}{3}.

$$a=\frac{\frac{b}{3}+2}{\frac{2}{3}}$$

Whakawehe 2+\frac{b}{3} ki te \frac{2}{3} mā te whakarea 2+\frac{b}{3} ki te tau huripoki o \frac{2}{3}.

$$a=\frac{b}{2}+3$$

Whakaoti mō b

$$b=2\left(a-3\right)$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tangohia te \frac{2}{3}a mai i ngā taha e rua.

$$-\frac{1}{3}b=2-\frac{2}{3}a$$

He hanga arowhānui tō te whārite.

$$-\frac{1}{3}b=-\frac{2a}{3}+2$$

Me whakarea ngā taha e rua ki te -3.

$$\frac{-\frac{1}{3}b}{-\frac{1}{3}}=\frac{-\frac{2a}{3}+2}{-\frac{1}{3}}$$

Mā te whakawehe ki te -\frac{1}{3} ka wetekia te whakareanga ki te -\frac{1}{3}.

$$b=\frac{-\frac{2a}{3}+2}{-\frac{1}{3}}$$

Whakawehe 2-\frac{2a}{3} ki te -\frac{1}{3} mā te whakarea 2-\frac{2a}{3} ki te tau huripoki o -\frac{1}{3}.

$$b=2a-6$$