Whakaoti i te 2/3-5x=bx+1/3

$$\frac { 2 } { 3 } - 5 x = b x + \frac { 1 } { 3 }$$

Whakaoti mō b

$$b=-5+\frac{1}{3x}$$

$$x\neq 0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$bx+\frac{1}{3}=\frac{2}{3}-5x$$

Tangohia te \frac{1}{3} mai i ngā taha e rua.

$$bx=\frac{2}{3}-5x-\frac{1}{3}$$

Tangohia te \frac{1}{3} i te \frac{2}{3}, ka \frac{1}{3}.

$$bx=\frac{1}{3}-5x$$

He hanga arowhānui tō te whārite.

$$xb=\frac{1}{3}-5x$$

Whakawehea ngā taha e rua ki te x.

$$\frac{xb}{x}=\frac{\frac{1}{3}-5x}{x}$$

Mā te whakawehe ki te x ka wetekia te whakareanga ki te x.

$$b=\frac{\frac{1}{3}-5x}{x}$$

Whakawehe \frac{1}{3}-5x ki te x.

$$b=-5+\frac{1}{3x}$$

Whakaoti mō x

$$x=\frac{1}{3\left(b+5\right)}$$

$$b\neq -5$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tangohia te bx mai i ngā taha e rua.

$$\frac{2}{3}-5x-bx=\frac{1}{3}$$

Tangohia te \frac{2}{3} mai i ngā taha e rua.

$$-5x-bx=\frac{1}{3}-\frac{2}{3}$$

Tangohia te \frac{2}{3} i te \frac{1}{3}, ka -\frac{1}{3}.

$$-5x-bx=-\frac{1}{3}$$

Pahekotia ngā kīanga tau katoa e whai ana i te x.

$$\left(-5-b\right)x=-\frac{1}{3}$$

He hanga arowhānui tō te whārite.

$$\left(-b-5\right)x=-\frac{1}{3}$$

Whakawehea ngā taha e rua ki te -5-b.

$$\frac{\left(-b-5\right)x}{-b-5}=-\frac{\frac{1}{3}}{-b-5}$$

Mā te whakawehe ki te -5-b ka wetekia te whakareanga ki te -5-b.

$$x=-\frac{\frac{1}{3}}{-b-5}$$

Whakawehe -\frac{1}{3} ki te -5-b.

$$x=\frac{1}{3\left(b+5\right)}$$