Whakaoti i te 2/3(x-3)=1/4(x+7)

$$\frac { 2 } { 3 } ( x - 3 ) = \frac { 1 } { 4 } ( x + 7 )$$

Whakaoti mō x

$$x=9$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te \frac{2}{3} ki te x-3.

$$\frac{2}{3}x+\frac{2}{3}\left(-3\right)=\frac{1}{4}\left(x+7\right)$$

Tuhia te \frac{2}{3}\left(-3\right) hei hautanga kotahi.

$$\frac{2}{3}x+\frac{2\left(-3\right)}{3}=\frac{1}{4}\left(x+7\right)$$

Whakareatia te 2 ki te -3, ka -6.

$$\frac{2}{3}x+\frac{-6}{3}=\frac{1}{4}\left(x+7\right)$$

Whakawehea te -6 ki te 3, kia riro ko -2.

$$\frac{2}{3}x-2=\frac{1}{4}\left(x+7\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te \frac{1}{4} ki te x+7.

$$\frac{2}{3}x-2=\frac{1}{4}x+\frac{1}{4}\times 7$$

Whakareatia te \frac{1}{4} ki te 7, ka \frac{7}{4}.

$$\frac{2}{3}x-2=\frac{1}{4}x+\frac{7}{4}$$

Tangohia te \frac{1}{4}x mai i ngā taha e rua.

$$\frac{2}{3}x-2-\frac{1}{4}x=\frac{7}{4}$$

Pahekotia te \frac{2}{3}x me -\frac{1}{4}x, ka \frac{5}{12}x.

$$\frac{5}{12}x-2=\frac{7}{4}$$

Me tāpiri te 2 ki ngā taha e rua.

$$\frac{5}{12}x=\frac{7}{4}+2$$

Me tahuri te 2 ki te hautau \frac{8}{4}.

$$\frac{5}{12}x=\frac{7}{4}+\frac{8}{4}$$

Tā te mea he rite te tauraro o \frac{7}{4} me \frac{8}{4}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$\frac{5}{12}x=\frac{7+8}{4}$$

Tāpirihia te 7 ki te 8, ka 15.

$$\frac{5}{12}x=\frac{15}{4}$$

Me whakarea ngā taha e rua ki te \frac{12}{5}, te tau utu o \frac{5}{12}.

$$x=\frac{15}{4}\times \frac{12}{5}$$

Me whakarea te \frac{15}{4} ki te \frac{12}{5} mā te whakarea taurunga ki te taurunga me te tauraro ki te tauraro.

$$x=\frac{15\times 12}{4\times 5}$$

Mahia ngā whakarea i roto i te hautanga \frac{15\times 12}{4\times 5}.

$$x=\frac{180}{20}$$

Whakawehea te 180 ki te 20, kia riro ko 9.

$$x=9$$