Whakaoti i te 2/3(x+1/8)=1/6x

$$\frac { 2 } { 3 } ( x + \frac { 1 } { 8 } ) = \frac { 1 } { 6 } x$$

Whakaoti mō x

$$x=-\frac{1}{6}\approx -0.166666667$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te \frac{2}{3} ki te x+\frac{1}{8}.

$$\frac{2}{3}x+\frac{2}{3}\times \frac{1}{8}=\frac{1}{6}x$$

Me whakarea te \frac{2}{3} ki te \frac{1}{8} mā te whakarea taurunga ki te taurunga me te tauraro ki te tauraro.

$$\frac{2}{3}x+\frac{2\times 1}{3\times 8}=\frac{1}{6}x$$

Mahia ngā whakarea i roto i te hautanga \frac{2\times 1}{3\times 8}.

$$\frac{2}{3}x+\frac{2}{24}=\frac{1}{6}x$$

Whakahekea te hautanga \frac{2}{24} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 2.

$$\frac{2}{3}x+\frac{1}{12}=\frac{1}{6}x$$

Tangohia te \frac{1}{6}x mai i ngā taha e rua.

$$\frac{2}{3}x+\frac{1}{12}-\frac{1}{6}x=0$$

Pahekotia te \frac{2}{3}x me -\frac{1}{6}x, ka \frac{1}{2}x.

$$\frac{1}{2}x+\frac{1}{12}=0$$

Tangohia te \frac{1}{12} mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$\frac{1}{2}x=-\frac{1}{12}$$

Me whakarea ngā taha e rua ki te 2, te tau utu o \frac{1}{2}.

$$x=-\frac{1}{12}\times 2$$

Tuhia te -\frac{1}{12}\times 2 hei hautanga kotahi.

$$x=\frac{-2}{12}$$

Whakahekea te hautanga \frac{-2}{12} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 2.

$$x=-\frac{1}{6}$$