Whakaoti i te 2/3(x+1/4)=x-1/4

$$\frac { 2 } { 3 } ( x + \frac { 1 } { 4 } ) = \frac { x - 1 } { 4 }$$

Whakaoti mō x

$$x=-1$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Me whakarea ngā taha e rua o te whārite ki te 12, arā, te tauraro pātahi he tino iti rawa te kitea o 3,4.

$$8\left(x+\frac{1}{4}\right)=3\left(x-1\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te 8 ki te x+\frac{1}{4}.

$$8x+8\times \frac{1}{4}=3\left(x-1\right)$$

Whakareatia te 8 ki te \frac{1}{4}, ka \frac{8}{4}.

$$8x+\frac{8}{4}=3\left(x-1\right)$$

Whakawehea te 8 ki te 4, kia riro ko 2.

$$8x+2=3\left(x-1\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te 3 ki te x-1.

$$8x+2=3x-3$$

Tangohia te 3x mai i ngā taha e rua.

$$8x+2-3x=-3$$

Pahekotia te 8x me -3x, ka 5x.

$$5x+2=-3$$

Tangohia te 2 mai i ngā taha e rua.

$$5x=-3-2$$

Tangohia te 2 i te -3, ka -5.

$$5x=-5$$

Whakawehea ngā taha e rua ki te 5.

$$x=\frac{-5}{5}$$

Whakawehea te -5 ki te 5, kia riro ko -1.

$$x=-1$$