Whakaoti i te frac{2sqrt{3}-sqrt{2}}{2sqrt{3}+sqrt{3}}

$$\frac { 2 \sqrt { 3 } - \sqrt { 2 } } { 2 \sqrt { 3 } + \sqrt { 3 } }$$

Aromātai

$$-\frac{\sqrt{6}}{9}+\frac{2}{3}\approx 0.39450114$$

Ngā Upane Otinga

Pahekotia te 2\sqrt{3} me \sqrt{3}, ka 3\sqrt{3}.

$$\frac{2\sqrt{3}-\sqrt{2}}{3\sqrt{3}}$$

Whakangāwaritia te tauraro o \frac{2\sqrt{3}-\sqrt{2}}{3\sqrt{3}} mā te whakarea i te taurunga me te tauraro ki te \sqrt{3}.

$$\frac{\left(2\sqrt{3}-\sqrt{2}\right)\sqrt{3}}{3\left(\sqrt{3}\right)^{2}}$$

Ko te pūrua o \sqrt{3} ko 3.

$$\frac{\left(2\sqrt{3}-\sqrt{2}\right)\sqrt{3}}{3\times 3}$$

Whakareatia te 3 ki te 3, ka 9.

$$\frac{\left(2\sqrt{3}-\sqrt{2}\right)\sqrt{3}}{9}$$

Whakamahia te āhuatanga tohatoha hei whakarea te 2\sqrt{3}-\sqrt{2} ki te \sqrt{3}.

$$\frac{2\left(\sqrt{3}\right)^{2}-\sqrt{2}\sqrt{3}}{9}$$

Ko te pūrua o \sqrt{3} ko 3.

$$\frac{2\times 3-\sqrt{2}\sqrt{3}}{9}$$

Whakareatia te 2 ki te 3, ka 6.

$$\frac{6-\sqrt{2}\sqrt{3}}{9}$$

Hei whakarea \sqrt{2} me \sqrt{3}, whakareatia ngā tau i raro i te pūtake rua.

$$\frac{6-\sqrt{6}}{9}$$

Tauwehe

$$\frac{\sqrt{6} {(\sqrt{6} - 1)}}{9} = 0.3945011396907579$$