Whakaoti i te 2^2x-1/y^2=c^2

$$\frac { 2 ^ { 2 } x - 1 } { y ^ { 2 } } = c ^ { 2 }$$

Whakaoti mō x

$$x=\frac{\left(cy\right)^{2}+1}{4}$$

$$y\neq 0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakareatia ngā taha e rua o te whārite ki te y^{2}.

$$2^{2}x-1=y^{2}c^{2}$$

Tātaihia te 2 mā te pū o 2, kia riro ko 4.

$$4x-1=y^{2}c^{2}$$

Me tāpiri te 1 ki ngā taha e rua.

$$4x=y^{2}c^{2}+1$$

He hanga arowhānui tō te whārite.

$$4x=c^{2}y^{2}+1$$

Whakawehea ngā taha e rua ki te 4.

$$\frac{4x}{4}=\frac{c^{2}y^{2}+1}{4}$$

Mā te whakawehe ki te 4 ka wetekia te whakareanga ki te 4.

$$x=\frac{c^{2}y^{2}+1}{4}$$

Whakaoti mō c (complex solution)

$$c=-\frac{\sqrt{4x-1}}{y}$$

$$c=\frac{\sqrt{4x-1}}{y}\text{, }y\neq 0$$

Whakaoti mō c

$$c=\frac{\sqrt{4x-1}}{|y|}$$

$$c=-\frac{\sqrt{4x-1}}{|y|}\text{, }x\geq \frac{1}{4}\text{ and }y\neq 0$$