Whakaoti i te 2+x/4+x/3-1-x/6=x/12+1

$$\frac { 2 + x } { 4 } + \frac { x } { 3 } - \frac { 1 - x } { 6 } = \frac { x } { 12 } + 1$$

Whakaoti mō x

$$x=1$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Me whakarea ngā taha e rua o te whārite ki te 12, arā, te tauraro pātahi he tino iti rawa te kitea o 4,3,6,12.

$$3\left(2+x\right)+4x-2\left(1-x\right)=x+12$$

Whakamahia te āhuatanga tohatoha hei whakarea te 3 ki te 2+x.

$$6+3x+4x-2\left(1-x\right)=x+12$$

Pahekotia te 3x me 4x, ka 7x.

$$6+7x-2\left(1-x\right)=x+12$$

Whakamahia te āhuatanga tohatoha hei whakarea te -2 ki te 1-x.

$$6+7x-2+2x=x+12$$

Tangohia te 2 i te 6, ka 4.

$$4+7x+2x=x+12$$

Pahekotia te 7x me 2x, ka 9x.

$$4+9x=x+12$$

Tangohia te x mai i ngā taha e rua.

$$4+9x-x=12$$

Pahekotia te 9x me -x, ka 8x.

$$4+8x=12$$

Tangohia te 4 mai i ngā taha e rua.

$$8x=12-4$$

Tangohia te 4 i te 12, ka 8.

$$8x=8$$

Whakawehea ngā taha e rua ki te 8.

$$x=\frac{8}{8}$$

Whakawehea te 8 ki te 8, kia riro ko 1.

$$x=1$$