Whakaoti i te 19/x^2+10x+25+3/x+5

$$\frac { 19 } { x ^ { 2 } + 10 x + 25 } + \frac { 3 } { x + 5 }$$

Aromātai

$$\frac{3x+34}{\left(x+5\right)^{2}}$$

Ngā Hipanga Rongoā Poto

Tauwehea te x^{2}+10x+25.

$$\frac{19}{\left(x+5\right)^{2}}+\frac{3}{x+5}$$

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Ko te taurea pātahi iti rawa o \left(x+5\right)^{2} me x+5 ko \left(x+5\right)^{2}. Whakareatia \frac{3}{x+5} ki te \frac{x+5}{x+5}.

$$\frac{19}{\left(x+5\right)^{2}}+\frac{3\left(x+5\right)}{\left(x+5\right)^{2}}$$

Tā te mea he rite te tauraro o \frac{19}{\left(x+5\right)^{2}} me \frac{3\left(x+5\right)}{\left(x+5\right)^{2}}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$\frac{19+3\left(x+5\right)}{\left(x+5\right)^{2}}$$

Mahia ngā whakarea i roto o 19+3\left(x+5\right).

$$\frac{19+3x+15}{\left(x+5\right)^{2}}$$

Whakakotahitia ngā kupu rite i 19+3x+15.

$$\frac{34+3x}{\left(x+5\right)^{2}}$$

Whakarohaina te \left(x+5\right)^{2}.

$$\frac{34+3x}{x^{2}+10x+25}$$

Kimi Pārōnaki e ai ki x

$$\frac{-3x-53}{\left(x+5\right)^{3}}$$