Whakaoti i te 18s^3t^3/24s^2t=

$$\frac { 18 s ^ { 3 } t ^ { 3 } } { 24 s ^ { 2 } t } =$$

Aromātai

$$\frac{3st^{2}}{4}$$

Ngā Upane e Whakamahi ana i te Āhuatanga o te Otinga o ngā Pū

Whakamahia ngā ture taupū hei whakarūnā i te kīanga.

$$\frac{18^{1}s^{3}t^{3}}{24^{1}s^{2}t^{1}}$$

Hei whakawehe i ngā pū o te pūtake kotahi, tangohia te taupū o te tauraro mai i te taupū o te taurunga.

$$\frac{18^{1}}{24^{1}}s^{3-2}t^{3-1}$$

Tango 2 mai i 3.

$$\frac{18^{1}}{24^{1}}s^{1}t^{3-1}$$

Tango 1 mai i 3.

$$\frac{18^{1}}{24^{1}}st^{2}$$

Whakahekea te hautanga \frac{18}{24} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 6.

$$\frac{3}{4}st^{2}$$

Kimi Pārōnaki e ai ki s

$$\frac{3t^{2}}{4}$$

Ngā Upane Otinga

Hei whakawehe i ngā pū o te pūtake kotahi, tangohia te taupū o te tauraro mai i te taupū o te taurunga.

$$\frac{\mathrm{d}}{\mathrm{d}s}(\frac{18t^{3}}{24t}s^{3-2})$$

Mahia ngā tātaitanga.

$$\frac{\mathrm{d}}{\mathrm{d}s}(\frac{3t^{2}}{4}s^{1})$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$\frac{3t^{2}}{4}s^{1-1}$$

Mahia ngā tātaitanga.

$$\frac{3t^{2}}{4}s^{0}$$

Mō tētahi kupu t mahue te 0, t^{0}=1.

$$\frac{3t^{2}}{4}\times 1$$

Mō tētahi kupu t, t\times 1=t me 1t=t.

$$\frac{3t^{2}}{4}$$