Whakaoti i te 15/4-3/2y-5y=7

$$\frac { 15 } { 4 } - \frac { 3 } { 2 } y - 5 y = 7$$

Whakaoti mō y

$$y=-\frac{1}{2}=-0.5$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Pahekotia te -\frac{3}{2}y me -5y, ka -\frac{13}{2}y.

$$\frac{15}{4}-\frac{13}{2}y=7$$

Tangohia te \frac{15}{4} mai i ngā taha e rua.

$$-\frac{13}{2}y=7-\frac{15}{4}$$

Me tahuri te 7 ki te hautau \frac{28}{4}.

$$-\frac{13}{2}y=\frac{28}{4}-\frac{15}{4}$$

Tā te mea he rite te tauraro o \frac{28}{4} me \frac{15}{4}, me tango rāua mā te tango i ō raua taurunga.

$$-\frac{13}{2}y=\frac{28-15}{4}$$

Tangohia te 15 i te 28, ka 13.

$$-\frac{13}{2}y=\frac{13}{4}$$

Me whakarea ngā taha e rua ki te -\frac{2}{13}, te tau utu o -\frac{13}{2}.

$$y=\frac{13}{4}\left(-\frac{2}{13}\right)$$

Me whakarea te \frac{13}{4} ki te -\frac{2}{13} mā te whakarea taurunga ki te taurunga me te tauraro ki te tauraro.

$$y=\frac{13\left(-2\right)}{4\times 13}$$

Me whakakore tahi te 13 i te taurunga me te tauraro.

$$y=\frac{-2}{4}$$

Whakahekea te hautanga \frac{-2}{4} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 2.

$$y=-\frac{1}{2}$$