Whakaoti i te 13/2=3(p+2)/2-2(p+1)/3

$$\frac { 13 } { 2 } = \frac { 3 ( p + 2 ) } { 2 } - \frac { 2 ( p + 1 ) } { 3 }$$

Whakaoti mō p

$$p=5$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Me whakarea ngā taha e rua o te whārite ki te 6, arā, te tauraro pātahi he tino iti rawa te kitea o 2,3.

$$39=3\times 3\left(p+2\right)-2\times 2\left(p+1\right)$$

Whakareatia te 3 ki te 3, ka 9. Whakareatia te -2 ki te 2, ka -4.

$$39=9\left(p+2\right)-4\left(p+1\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te 9 ki te p+2.

$$39=9p+18-4\left(p+1\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te -4 ki te p+1.

$$39=9p+18-4p-4$$

Pahekotia te 9p me -4p, ka 5p.

$$39=5p+18-4$$

Tangohia te 4 i te 18, ka 14.

$$39=5p+14$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$5p+14=39$$

Tangohia te 14 mai i ngā taha e rua.

$$5p=39-14$$

Tangohia te 14 i te 39, ka 25.

$$5p=25$$

Whakawehea ngā taha e rua ki te 5.

$$p=\frac{25}{5}$$

Whakawehea te 25 ki te 5, kia riro ko 5.

$$p=5$$