Whakaoti i te 12/503-xgeq3x+5

$$\frac { 12 } { 50 } 3 - x \geq 3 x + 5$$

Whakaoti mō x

$$x\leq -\frac{107}{100}$$

Ngā Upane Otinga

Whakahekea te hautanga \frac{12}{50} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 2.

$$\frac{6}{25}\times 3-x\geq 3x+5$$

Tuhia te \frac{6}{25}\times 3 hei hautanga kotahi.

$$\frac{6\times 3}{25}-x\geq 3x+5$$

Whakareatia te 6 ki te 3, ka 18.

$$\frac{18}{25}-x\geq 3x+5$$

Tangohia te 3x mai i ngā taha e rua.

$$\frac{18}{25}-x-3x\geq 5$$

Pahekotia te -x me -3x, ka -4x.

$$\frac{18}{25}-4x\geq 5$$

Tangohia te \frac{18}{25} mai i ngā taha e rua.

$$-4x\geq 5-\frac{18}{25}$$

Me tahuri te 5 ki te hautau \frac{125}{25}.

$$-4x\geq \frac{125}{25}-\frac{18}{25}$$

Tā te mea he rite te tauraro o \frac{125}{25} me \frac{18}{25}, me tango rāua mā te tango i ō raua taurunga.

$$-4x\geq \frac{125-18}{25}$$

Tangohia te 18 i te 125, ka 107.

$$-4x\geq \frac{107}{25}$$

Whakawehea ngā taha e rua ki te -4. I te mea he tōraro a -4, ka huri te ahunga koreōrite.

$$x\leq \frac{\frac{107}{25}}{-4}$$

Tuhia te \frac{\frac{107}{25}}{-4} hei hautanga kotahi.

$$x\leq \frac{107}{25\left(-4\right)}$$

Whakareatia te 25 ki te -4, ka -100.

$$x\leq \frac{107}{-100}$$

Ka taea te hautanga \frac{107}{-100} te tuhi anō ko -\frac{107}{100} mā te tango i te tohu tōraro.

$$x\leq -\frac{107}{100}$$