Whakaoti i te 104i/5+i

$$\frac { 104 i } { 5 + i }$$

Aromātai

$$4+20i$$

Ngā Upane Otinga

Whakareatia te taurunga me te tauraro ki te haumi hiato o te tauraro, 5-i.

$$\frac{104i\left(5-i\right)}{\left(5+i\right)\left(5-i\right)}$$

Ka taea te whakareanga te panoni ki te rerekētanga o ngā pūrua mā te ture: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$\frac{104i\left(5-i\right)}{5^{2}-i^{2}}$$

Hei tōna tikanga, ko te i^{2} ko -1. Tātaitia te tauraro.

$$\frac{104i\left(5-i\right)}{26}$$

Whakareatia 104i ki te 5-i.

$$\frac{104i\times 5+104\left(-1\right)i^{2}}{26}$$

Hei tōna tikanga, ko te i^{2} ko -1.

$$\frac{104i\times 5+104\left(-1\right)\left(-1\right)}{26}$$

Mahia ngā whakarea i roto o 104i\times 5+104\left(-1\right)\left(-1\right). Whakaraupapatia anō ngā kīanga tau.

$$\frac{104+520i}{26}$$

Whakawehea te 104+520i ki te 26, kia riro ko 4+20i.

$$4+20i$$

Wāhi Tūturu

$$4$$

Ngā Upane Otinga

Me whakarea te taurunga me te tauraro o \frac{104i}{5+i} ki te haumi hiato o te tauraro, 5-i.

$$Re(\frac{104i\left(5-i\right)}{\left(5+i\right)\left(5-i\right)})$$

Ka taea te whakareanga te panoni ki te rerekētanga o ngā pūrua mā te ture: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$Re(\frac{104i\left(5-i\right)}{5^{2}-i^{2}})$$

Hei tōna tikanga, ko te i^{2} ko -1. Tātaitia te tauraro.

$$Re(\frac{104i\left(5-i\right)}{26})$$

Whakareatia 104i ki te 5-i.

$$Re(\frac{104i\times 5+104\left(-1\right)i^{2}}{26})$$

Hei tōna tikanga, ko te i^{2} ko -1.

$$Re(\frac{104i\times 5+104\left(-1\right)\left(-1\right)}{26})$$

Mahia ngā whakarea i roto o 104i\times 5+104\left(-1\right)\left(-1\right). Whakaraupapatia anō ngā kīanga tau.

$$Re(\frac{104+520i}{26})$$

Whakawehea te 104+520i ki te 26, kia riro ko 4+20i.

$$Re(4+20i)$$

Ko te wāhi tūturu o 4+20i ko 4.

$$4$$