Whakaoti i te 10/x-3-3

$$\frac { 10 } { x - 3 } - 3$$

Aromātai

$$\frac{19-3x}{x-3}$$

Ngā Hipanga Rongoā Poto

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Whakareatia 3 ki te \frac{x-3}{x-3}.

$$\frac{10}{x-3}-\frac{3\left(x-3\right)}{x-3}$$

Tā te mea he rite te tauraro o \frac{10}{x-3} me \frac{3\left(x-3\right)}{x-3}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{10-3\left(x-3\right)}{x-3}$$

Mahia ngā whakarea i roto o 10-3\left(x-3\right).

$$\frac{10-3x+9}{x-3}$$

Whakakotahitia ngā kupu rite i 10-3x+9.

$$\frac{19-3x}{x-3}$$

Kimi Pārōnaki e ai ki x

$$-\frac{10}{\left(x-3\right)^{2}}$$

Ngā Upane e Whakamahi ana i te Ture Pārōnaki mō te Otinga

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Whakareatia 3 ki te \frac{x-3}{x-3}.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{10}{x-3}-\frac{3\left(x-3\right)}{x-3})$$

Tā te mea he rite te tauraro o \frac{10}{x-3} me \frac{3\left(x-3\right)}{x-3}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{10-3\left(x-3\right)}{x-3})$$

Mahia ngā whakarea i roto o 10-3\left(x-3\right).

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{10-3x+9}{x-3})$$

Whakakotahitia ngā kupu rite i 10-3x+9.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{19-3x}{x-3})$$

Mō ngā pānga e rua e taea ana te pārōnaki, ko te pārōnaki o te otinga o ngā pānga e rua ko te tauraro whakareatia ki te pārōnaki o te taurunga tango i te taurunga whakareatia ki te pārōnaki o te tauraro, ā, ka whakawehea te katoa ki te tauraro kua pūruatia.

$$\frac{\left(x^{1}-3\right)\frac{\mathrm{d}}{\mathrm{d}x}(-3x^{1}+19)-\left(-3x^{1}+19\right)\frac{\mathrm{d}}{\mathrm{d}x}(x^{1}-3)}{\left(x^{1}-3\right)^{2}}$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$\frac{\left(x^{1}-3\right)\left(-3\right)x^{1-1}-\left(-3x^{1}+19\right)x^{1-1}}{\left(x^{1}-3\right)^{2}}$$

Mahia ngā tātaitanga.

$$\frac{\left(x^{1}-3\right)\left(-3\right)x^{0}-\left(-3x^{1}+19\right)x^{0}}{\left(x^{1}-3\right)^{2}}$$

Whakarohaina mā te āhuatanga tohatoha.

$$\frac{x^{1}\left(-3\right)x^{0}-3\left(-3\right)x^{0}-\left(-3x^{1}x^{0}+19x^{0}\right)}{\left(x^{1}-3\right)^{2}}$$

Hei whakarea pū o te pūtake ōrite, tāpiri ana taupū.

$$\frac{-3x^{1}-3\left(-3\right)x^{0}-\left(-3x^{1}+19x^{0}\right)}{\left(x^{1}-3\right)^{2}}$$

Mahia ngā tātaitanga.

$$\frac{-3x^{1}+9x^{0}-\left(-3x^{1}+19x^{0}\right)}{\left(x^{1}-3\right)^{2}}$$

Tangohia ngā taiapa kāore i te hiahiatia.

$$\frac{-3x^{1}+9x^{0}-\left(-3x^{1}\right)-19x^{0}}{\left(x^{1}-3\right)^{2}}$$

Pahekotia ngā kīanga tau ōrite.

$$\frac{\left(-3-\left(-3\right)\right)x^{1}+\left(9-19\right)x^{0}}{\left(x^{1}-3\right)^{2}}$$

Tangohia te -3 i -3 me te 19 i te 9.

$$\frac{-10x^{0}}{\left(x^{1}-3\right)^{2}}$$

Mō tētahi kupu t, t^{1}=t.

$$\frac{-10x^{0}}{\left(x-3\right)^{2}}$$

Mō tētahi kupu t mahue te 0, t^{0}=1.

$$\frac{-10}{\left(x-3\right)^{2}}$$