Whakaoti i te 10/x+1=15/4(x+2)

$$\frac { 10 } { x + 1 } = \frac { 15 } { 4 ( x + 2 ) }$$

Whakaoti mō x

$$x = -\frac{13}{5} = -2\frac{3}{5} = -2.6$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tē taea kia ōrite te tāupe x ki tētahi o ngā uara -2,-1 nā te kore tautuhi i te whakawehenga mā te kore. Me whakarea ngā taha e rua o te whārite ki te 4\left(x+1\right)\left(x+2\right), arā, te tauraro pātahi he tino iti rawa te kitea o x+1,4\left(x+2\right).

$$\left(4x+8\right)\times 10=\left(x+1\right)\times 15$$

Whakamahia te āhuatanga tohatoha hei whakarea te 4x+8 ki te 10.

$$40x+80=\left(x+1\right)\times 15$$

Whakamahia te āhuatanga tohatoha hei whakarea te x+1 ki te 15.

$$40x+80=15x+15$$

Tangohia te 15x mai i ngā taha e rua.

$$40x+80-15x=15$$

Pahekotia te 40x me -15x, ka 25x.

$$25x+80=15$$

Tangohia te 80 mai i ngā taha e rua.

$$25x=15-80$$

Tangohia te 80 i te 15, ka -65.

$$25x=-65$$

Whakawehea ngā taha e rua ki te 25.

$$x=\frac{-65}{25}$$

Whakahekea te hautanga \frac{-65}{25} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 5.

$$x=-\frac{13}{5}$$