Whakaoti i te 1/x-4-1/(x-4)(x+2)

$$\frac { 1 } { x - 4 } - \frac { 1 } { ( x - 4 ) ( x + 2 ) }$$

Aromātai

$$\frac{x+1}{\left(x-4\right)\left(x+2\right)}$$

Ngā Hipanga Rongoā Poto

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Ko te taurea pātahi iti rawa o x-4 me \left(x-4\right)\left(x+2\right) ko \left(x-4\right)\left(x+2\right). Whakareatia \frac{1}{x-4} ki te \frac{x+2}{x+2}.

$$\frac{x+2}{\left(x-4\right)\left(x+2\right)}-\frac{1}{\left(x-4\right)\left(x+2\right)}$$

Tā te mea he rite te tauraro o \frac{x+2}{\left(x-4\right)\left(x+2\right)} me \frac{1}{\left(x-4\right)\left(x+2\right)}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{x+2-1}{\left(x-4\right)\left(x+2\right)}$$

Whakakotahitia ngā kupu rite i x+2-1.

$$\frac{x+1}{\left(x-4\right)\left(x+2\right)}$$

Whakarohaina te \left(x-4\right)\left(x+2\right).

$$\frac{x+1}{x^{2}-2x-8}$$

Whakaroha

$$\frac{x+1}{\left(x-4\right)\left(x+2\right)}$$

Ngā Hipanga Rongoā Poto

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Ko te taurea pātahi iti rawa o x-4 me \left(x-4\right)\left(x+2\right) ko \left(x-4\right)\left(x+2\right). Whakareatia \frac{1}{x-4} ki te \frac{x+2}{x+2}.

$$\frac{x+2}{\left(x-4\right)\left(x+2\right)}-\frac{1}{\left(x-4\right)\left(x+2\right)}$$

Tā te mea he rite te tauraro o \frac{x+2}{\left(x-4\right)\left(x+2\right)} me \frac{1}{\left(x-4\right)\left(x+2\right)}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{x+2-1}{\left(x-4\right)\left(x+2\right)}$$

Whakakotahitia ngā kupu rite i x+2-1.

$$\frac{x+1}{\left(x-4\right)\left(x+2\right)}$$

Whakarohaina te \left(x-4\right)\left(x+2\right).

$$\frac{x+1}{x^{2}-2x-8}$$