Whakaoti i te 1/x-2=sqrt[3]{5}

$$\frac { 1 } { x - 2 } = \sqrt[ 3 ] { 5 }$$

Whakaoti mō x

$$x = \frac{5 ^ {\frac{2}{3}} + 10}{5} \approx 2.584803548$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tē taea kia ōrite te tāupe x ki 2 nā te kore tautuhi i te whakawehenga mā te kore. Whakareatia ngā taha e rua o te whārite ki te x-2.

$$1=\left(x-2\right)\sqrt[3]{5}$$

Whakamahia te āhuatanga tohatoha hei whakarea te x-2 ki te \sqrt[3]{5}.

$$1=x\sqrt[3]{5}-2\sqrt[3]{5}$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$x\sqrt[3]{5}-2\sqrt[3]{5}=1$$

Me tāpiri te 2\sqrt[3]{5} ki ngā taha e rua.

$$x\sqrt[3]{5}=1+2\sqrt[3]{5}$$

He hanga arowhānui tō te whārite.

$$\sqrt[3]{5}x=2\sqrt[3]{5}+1$$

Whakawehea ngā taha e rua ki te \sqrt[3]{5}.

$$\frac{\sqrt[3]{5}x}{\sqrt[3]{5}}=\frac{2\sqrt[3]{5}+1}{\sqrt[3]{5}}$$

Mā te whakawehe ki te \sqrt[3]{5} ka wetekia te whakareanga ki te \sqrt[3]{5}.

$$x=\frac{2\sqrt[3]{5}+1}{\sqrt[3]{5}}$$

Whakawehe 1+2\sqrt[3]{5} ki te \sqrt[3]{5}.

$$x=\frac{1}{\sqrt[3]{5}}+2$$