Whakaoti i te 1/x+1/n=n/n+n

$$\frac { 1 } { x } + \frac { 1 } { n } = \frac { n } { n + n }$$

Whakaoti mō n

$$n=-\frac{2x}{2-x}$$

$$x\neq 0\text{ and }x\neq 2$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tē taea kia ōrite te tāupe n ki 0 nā te kore tautuhi i te whakawehenga mā te kore. Me whakarea ngā taha e rua o te whārite ki te 2nx, arā, te tauraro pātahi he tino iti rawa te kitea o x,n,n+n.

$$2n+2x=xn$$

Tangohia te xn mai i ngā taha e rua.

$$2n+2x-xn=0$$

Tangohia te 2x mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$2n-xn=-2x$$

Pahekotia ngā kīanga tau katoa e whai ana i te n.

$$\left(2-x\right)n=-2x$$

Whakawehea ngā taha e rua ki te 2-x.

$$\frac{\left(2-x\right)n}{2-x}=-\frac{2x}{2-x}$$

Mā te whakawehe ki te 2-x ka wetekia te whakareanga ki te 2-x.

$$n=-\frac{2x}{2-x}$$

Tē taea kia ōrite te tāupe n ki 0.

$$n=-\frac{2x}{2-x}\text{, }n\neq 0$$

Whakaoti mō x

$$x=-\frac{2n}{2-n}$$

$$n\neq 0\text{ and }n\neq 2$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tē taea kia ōrite te tāupe x ki 0 nā te kore tautuhi i te whakawehenga mā te kore. Me whakarea ngā taha e rua o te whārite ki te 2nx, arā, te tauraro pātahi he tino iti rawa te kitea o x,n,n+n.

$$2n+2x=xn$$

Tangohia te xn mai i ngā taha e rua.

$$2n+2x-xn=0$$

Tangohia te 2n mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$2x-xn=-2n$$

Pahekotia ngā kīanga tau katoa e whai ana i te x.

$$\left(2-n\right)x=-2n$$

Whakawehea ngā taha e rua ki te 2-n.

$$\frac{\left(2-n\right)x}{2-n}=-\frac{2n}{2-n}$$

Mā te whakawehe ki te 2-n ka wetekia te whakareanga ki te 2-n.

$$x=-\frac{2n}{2-n}$$

Tē taea kia ōrite te tāupe x ki 0.

$$x=-\frac{2n}{2-n}\text{, }x\neq 0$$