Whakaoti i te 1/x^2-4+1/x^2-4x+4

$$\frac { 1 } { x ^ { 2 } - 4 } + \frac { 1 } { x ^ { 2 } - 4 x + 4 }$$

Aromātai

$$\frac{2x}{\left(x+2\right)\left(x-2\right)^{2}}$$

Ngā Hipanga Rongoā Poto

Tauwehea te x^{2}-4. Tauwehea te x^{2}-4x+4.

$$\frac{1}{\left(x-2\right)\left(x+2\right)}+\frac{1}{\left(x-2\right)^{2}}$$

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Ko te taurea pātahi iti rawa o \left(x-2\right)\left(x+2\right) me \left(x-2\right)^{2} ko \left(x+2\right)\left(x-2\right)^{2}. Whakareatia \frac{1}{\left(x-2\right)\left(x+2\right)} ki te \frac{x-2}{x-2}. Whakareatia \frac{1}{\left(x-2\right)^{2}} ki te \frac{x+2}{x+2}.

$$\frac{x-2}{\left(x+2\right)\left(x-2\right)^{2}}+\frac{x+2}{\left(x+2\right)\left(x-2\right)^{2}}$$

Tā te mea he rite te tauraro o \frac{x-2}{\left(x+2\right)\left(x-2\right)^{2}} me \frac{x+2}{\left(x+2\right)\left(x-2\right)^{2}}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$\frac{x-2+x+2}{\left(x+2\right)\left(x-2\right)^{2}}$$

Whakakotahitia ngā kupu rite i x-2+x+2.

$$\frac{2x}{\left(x+2\right)\left(x-2\right)^{2}}$$

Whakarohaina te \left(x+2\right)\left(x-2\right)^{2}.

$$\frac{2x}{x^{3}-2x^{2}-4x+8}$$

Kimi Pārōnaki e ai ki x

$$-\frac{4\left(x^{2}+x+2\right)}{\left(x+2\right)^{2}\left(x-2\right)^{3}}$$