Whakaoti i te 1/x^2-16+1/2x-8

$$\frac { 1 } { x ^ { 2 } - 16 } + \frac { 1 } { 2 x - 8 }$$

Aromātai

$$\frac{x+6}{2\left(x^{2}-16\right)}$$

Ngā Hipanga Rongoā Poto

Tauwehea te x^{2}-16. Tauwehea te 2x-8.

$$\frac{1}{\left(x-4\right)\left(x+4\right)}+\frac{1}{2\left(x-4\right)}$$

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Ko te taurea pātahi iti rawa o \left(x-4\right)\left(x+4\right) me 2\left(x-4\right) ko 2\left(x-4\right)\left(x+4\right). Whakareatia \frac{1}{\left(x-4\right)\left(x+4\right)} ki te \frac{2}{2}. Whakareatia \frac{1}{2\left(x-4\right)} ki te \frac{x+4}{x+4}.

$$\frac{2}{2\left(x-4\right)\left(x+4\right)}+\frac{x+4}{2\left(x-4\right)\left(x+4\right)}$$

Tā te mea he rite te tauraro o \frac{2}{2\left(x-4\right)\left(x+4\right)} me \frac{x+4}{2\left(x-4\right)\left(x+4\right)}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$\frac{2+x+4}{2\left(x-4\right)\left(x+4\right)}$$

Whakakotahitia ngā kupu rite i 2+x+4.

$$\frac{6+x}{2\left(x-4\right)\left(x+4\right)}$$

Whakarohaina te 2\left(x-4\right)\left(x+4\right).

$$\frac{6+x}{2x^{2}-32}$$

Tauwehe

$$\frac{x+6}{2\left(x^{2}-16\right)}$$