Whakaoti i te 1/x^2+x+1/x^2-x

$$\frac { 1 } { x ^ { 2 } + x } + \frac { 1 } { x ^ { 2 } - x }$$

Aromātai

$$\frac{2}{x^{2}-1}$$

Ngā Hipanga Rongoā Poto

Tauwehea te x^{2}+x. Tauwehea te x^{2}-x.

$$\frac{1}{x\left(x+1\right)}+\frac{1}{x\left(x-1\right)}$$

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Ko te taurea pātahi iti rawa o x\left(x+1\right) me x\left(x-1\right) ko x\left(x-1\right)\left(x+1\right). Whakareatia \frac{1}{x\left(x+1\right)} ki te \frac{x-1}{x-1}. Whakareatia \frac{1}{x\left(x-1\right)} ki te \frac{x+1}{x+1}.

$$\frac{x-1}{x\left(x-1\right)\left(x+1\right)}+\frac{x+1}{x\left(x-1\right)\left(x+1\right)}$$

Tā te mea he rite te tauraro o \frac{x-1}{x\left(x-1\right)\left(x+1\right)} me \frac{x+1}{x\left(x-1\right)\left(x+1\right)}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$\frac{x-1+x+1}{x\left(x-1\right)\left(x+1\right)}$$

Whakakotahitia ngā kupu rite i x-1+x+1.

$$\frac{2x}{x\left(x-1\right)\left(x+1\right)}$$

Me whakakore tahi te x i te taurunga me te tauraro.

$$\frac{2}{\left(x-1\right)\left(x+1\right)}$$

Whakarohaina te \left(x-1\right)\left(x+1\right).

$$\frac{2}{x^{2}-1}$$

Kimi Pārōnaki e ai ki x

$$-\frac{4x}{\left(x^{2}-1\right)^{2}}$$