Whakaoti i te 1/x+1+x+3/(x-2)(x+1)=7x/(x+1)(x-2)-x/(x+1)

$$\frac { 1 } { x + 1 } + \frac { x + 3 } { ( x - 2 ) ( x + 1 ) } = \frac { 7 x } { ( x + 1 ) ( x - 2 ) } - \frac { x } { ( x + 1 ) }$$

Whakaoti mō x

$$x = \frac{3 \sqrt{5} + 7}{2} \approx 6.854101966$$

$$x=\frac{7-3\sqrt{5}}{2}\approx 0.145898034$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tē taea kia ōrite te tāupe x ki tētahi o ngā uara -1,2 nā te kore tautuhi i te whakawehenga mā te kore. Me whakarea ngā taha e rua o te whārite ki te \left(x-2\right)\left(x+1\right), arā, te tauraro pātahi he tino iti rawa te kitea o x+1,\left(x-2\right)\left(x+1\right).

$$x-2+x+3=7x-\left(x-2\right)x$$

Pahekotia te x me x, ka 2x.

$$2x-2+3=7x-\left(x-2\right)x$$

Tāpirihia te -2 ki te 3, ka 1.

$$2x+1=7x-\left(x-2\right)x$$

Whakamahia te āhuatanga tohatoha hei whakarea te x-2 ki te x.

$$2x+1=7x-\left(x^{2}-2x\right)$$

Hei kimi i te tauaro o x^{2}-2x, kimihia te tauaro o ia taurangi.

$$2x+1=7x-x^{2}+2x$$

Pahekotia te 7x me 2x, ka 9x.

$$2x+1=9x-x^{2}$$

Tangohia te 9x mai i ngā taha e rua.

$$2x+1-9x=-x^{2}$$

Pahekotia te 2x me -9x, ka -7x.

$$-7x+1=-x^{2}$$

Me tāpiri te x^{2} ki ngā taha e rua.

$$-7x+1+x^{2}=0$$

Ko ngā whārite katoa o te āhua ax^{2}+bx+c=0 ka taea te whakaoti mā te whakamahi i te tikanga tātai pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. E rua ngā otinga ka puta i te tikanga tātai pūrua, ko tētahi ina he tāpiri a ±, ā, ko tētahi ina he tango.

$$x^{2}-7x+1=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, -7 mō b, me 1 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{-\left(-7\right)±\sqrt{\left(-7\right)^{2}-4}}{2}$$

Pūrua -7.

$$x=\frac{-\left(-7\right)±\sqrt{49-4}}{2}$$

Tāpiri 49 ki te -4.

$$x=\frac{-\left(-7\right)±\sqrt{45}}{2}$$

Tuhia te pūtakerua o te 45.

$$x=\frac{-\left(-7\right)±3\sqrt{5}}{2}$$

Ko te tauaro o -7 ko 7.

$$x=\frac{7±3\sqrt{5}}{2}$$

Nā, me whakaoti te whārite x=\frac{7±3\sqrt{5}}{2} ina he tāpiri te ±. Tāpiri 7 ki te 3\sqrt{5}.

$$x=\frac{3\sqrt{5}+7}{2}$$

Nā, me whakaoti te whārite x=\frac{7±3\sqrt{5}}{2} ina he tango te ±. Tango 3\sqrt{5} mai i 7.

$$x=\frac{7-3\sqrt{5}}{2}$$

Kua oti te whārite te whakatau.

$$x=\frac{3\sqrt{5}+7}{2} x=\frac{7-3\sqrt{5}}{2}$$

Ngā Upane mō te Whakaoti i te Pūrua

Tē taea kia ōrite te tāupe x ki tētahi o ngā uara -1,2 nā te kore tautuhi i te whakawehenga mā te kore. Me whakarea ngā taha e rua o te whārite ki te \left(x-2\right)\left(x+1\right), arā, te tauraro pātahi he tino iti rawa te kitea o x+1,\left(x-2\right)\left(x+1\right).

$$x-2+x+3=7x-\left(x-2\right)x$$

Pahekotia te x me x, ka 2x.

$$2x-2+3=7x-\left(x-2\right)x$$

Tāpirihia te -2 ki te 3, ka 1.

$$2x+1=7x-\left(x-2\right)x$$

Whakamahia te āhuatanga tohatoha hei whakarea te x-2 ki te x.

$$2x+1=7x-\left(x^{2}-2x\right)$$

Hei kimi i te tauaro o x^{2}-2x, kimihia te tauaro o ia taurangi.

$$2x+1=7x-x^{2}+2x$$

Pahekotia te 7x me 2x, ka 9x.

$$2x+1=9x-x^{2}$$

Tangohia te 9x mai i ngā taha e rua.

$$2x+1-9x=-x^{2}$$

Pahekotia te 2x me -9x, ka -7x.

$$-7x+1=-x^{2}$$

Me tāpiri te x^{2} ki ngā taha e rua.

$$-7x+1+x^{2}=0$$

Tangohia te 1 mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$-7x+x^{2}=-1$$

Ko ngā whārite pūrua pēnei i tēnei nā ka taea te whakaoti mā te whakaoti i te pūrua. Hei whakaoti i te pūrua, ko te whārite me mātua tuhi ki te āhua x^{2}+bx=c.

$$x^{2}-7x=-1$$

Whakawehea te -7, te tau whakarea o te kīanga tau x, ki te 2 kia riro ai te -\frac{7}{2}. Nā, tāpiria te pūrua o te -\frac{7}{2} ki ngā taha e rua o te whārite. Mā konei e pūrua tika tonu ai te taha mauī o te whārite.

$$x^{2}-7x+\left(-\frac{7}{2}\right)^{2}=-1+\left(-\frac{7}{2}\right)^{2}$$

Pūruatia -\frac{7}{2} mā te pūrua i te taurunga me te tauraro o te hautanga.

$$x^{2}-7x+\frac{49}{4}=-1+\frac{49}{4}$$

Tāpiri -1 ki te \frac{49}{4}.

$$x^{2}-7x+\frac{49}{4}=\frac{45}{4}$$

Tauwehea x^{2}-7x+\frac{49}{4}. Ko te tikanga pūnoa, ina ko x^{2}+bx+c he pūrua tika pūrua tika pū, ka taea taua mea te tauwehea i ngā wā katoa hei \left(x+\frac{b}{2}\right)^{2}.

$$\left(x-\frac{7}{2}\right)^{2}=\frac{45}{4}$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$\sqrt{\left(x-\frac{7}{2}\right)^{2}}=\sqrt{\frac{45}{4}}$$

Whakarūnātia.

$$x-\frac{7}{2}=\frac{3\sqrt{5}}{2} x-\frac{7}{2}=-\frac{3\sqrt{5}}{2}$$

Me tāpiri \frac{7}{2} ki ngā taha e rua o te whārite.

$$x=\frac{3\sqrt{5}+7}{2} x=\frac{7-3\sqrt{5}}{2}$$