Whakaoti i te 1/h(-4)=1/2x-2

$$\frac { 1 } { h ( - 4 ) } = \frac { 1 } { 2 } x - 2$$

Whakaoti mō h

$$h=-\frac{1}{2\left(x-4\right)}$$

$$x\neq 4$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tē taea kia ōrite te tāupe h ki 0 nā te kore tautuhi i te whakawehenga mā te kore. Me whakarea ngā taha e rua o te whārite ki te 4h, arā, te tauraro pātahi he tino iti rawa te kitea o h\left(-4\right),2.

$$-1=\frac{1}{2}x\times 4h+4h\left(-2\right)$$

Whakareatia te \frac{1}{2} ki te 4, ka 2.

$$-1=2xh+4h\left(-2\right)$$

Whakareatia te 4 ki te -2, ka -8.

$$-1=2xh-8h$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$2xh-8h=-1$$

Pahekotia ngā kīanga tau katoa e whai ana i te h.

$$\left(2x-8\right)h=-1$$

Whakawehea ngā taha e rua ki te 2x-8.

$$\frac{\left(2x-8\right)h}{2x-8}=-\frac{1}{2x-8}$$

Mā te whakawehe ki te 2x-8 ka wetekia te whakareanga ki te 2x-8.

$$h=-\frac{1}{2x-8}$$

Whakawehe -1 ki te 2x-8.

$$h=-\frac{1}{2\left(x-4\right)}$$

Tē taea kia ōrite te tāupe h ki 0.

$$h=-\frac{1}{2\left(x-4\right)}\text{, }h\neq 0$$

Whakaoti mō x

$$x=4-\frac{1}{2h}$$

$$h\neq 0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Me whakarea ngā taha e rua o te whārite ki te 4h, arā, te tauraro pātahi he tino iti rawa te kitea o h\left(-4\right),2.

$$-1=\frac{1}{2}x\times 4h+4h\left(-2\right)$$

Whakareatia te \frac{1}{2} ki te 4, ka 2.

$$-1=2xh+4h\left(-2\right)$$

Whakareatia te 4 ki te -2, ka -8.

$$-1=2xh-8h$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$2xh-8h=-1$$

Me tāpiri te 8h ki ngā taha e rua.

$$2xh=-1+8h$$

He hanga arowhānui tō te whārite.

$$2hx=8h-1$$

Whakawehea ngā taha e rua ki te 2h.

$$\frac{2hx}{2h}=\frac{8h-1}{2h}$$

Mā te whakawehe ki te 2h ka wetekia te whakareanga ki te 2h.

$$x=\frac{8h-1}{2h}$$

Whakawehe -1+8h ki te 2h.

$$x=4-\frac{1}{2h}$$